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Alekssandra [29.7K]
3 years ago
9

......................help

Mathematics
1 answer:
pantera1 [17]3 years ago
7 0

Answer:

its 2.4

Step-by-step explanation:

You might be interested in
Use interval notation to express the set of real numbers x that satisfies the inequality (x+2)(x-5) < 0.
azamat

The interval notation to express the set of real numbers <u>x</u> that satisfies the given inequality is -2<x<5. You also can represent it as (-2,5)

<h3>Inequality</h3>

It is an expression mathematical that represents a non-equal relationship between a number or another algebraic expression. Therefore, it is common the use following symbols: ≤ (less than or equal to), ≥ (greater than or equal to), < (less than), and > (greater than).

The solutions for inequalities can be given by: a graph in a number line or numbers.

For solving this exercise, it is necessary to find a number solution for the given inequality.

First, you should find the critical points of the inequality.

x+2=0

x = -2

and

x-5=0

x=5

Write, the intervals in between critical points. Therefore, -2<x<5.

Read more about inequalities here.

brainly.com/question/25275758

#SPJ1

8 0
1 year ago
Need help will mark brainliest
geniusboy [140]

Ans67

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Does anyone know this? its for a test , please ?!
konstantin123 [22]

Answer:

11) Irrational number

12) Integer

13) Communitive property of addition

14) Distributive property of addition and multipacation

15) 26

16) 8

17) -41

18) 65

19) -5x-20

Step-by-step explanation:

Hope I helped

4 0
3 years ago
26. (02.08)
Mama L [17]

Answer:

X^2 -5x -36

Step-by-step explanation:

formula of an area of a rectangle: ab

a-length

b-width

(x+4)*(x-9) = x^2 -5x -36

7 0
2 years ago
According tot he rational root theorem, which statement about f(x)=12x^3-5x^2+6x+9 is true?
vampirchik [111]

Answer:

If there are any rational roots, it would be a factor of your constant term (9) divided by a factor of the high-order coefficient (12).

3 0
3 years ago
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