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alina1380 [7]
2 years ago
13

2. If r=7 is a solution to -6r+18=k(x-15), then which of the following must be the value of K?

Mathematics
1 answer:
Radda [10]2 years ago
6 0

Answer: (1)-8

Step-by-step explanation: −6r+18=k(x−15)

Step 1: Flip the equation.

kx−15k=−6r+18

Step 2: Factor out variable k.

k(x−15)=−6r+18

Step 3: Divide both sides by x-15.

k(x−15)/x-15 =

−6r+18/x-15

k= −6r+18/x-15= -8

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Step-by-step explanation:

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to get the area of the shaded part, we need to calculate the area of the large triangle and subtract the area of the smaller triangle.

large area :

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4 0
3 years ago
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Dmitry [639]

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I could be mistaken but I believe that x= 42.5

Step-by-step explanation:

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8 0
3 years ago
-3(x - 5) = 3x + 15
Travka [436]

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6 0
3 years ago
A collar of Styrofoam is made to insulate a pipe. Find it's volume. That large R is to the outer rim. The smaller r us to the ed
anastassius [24]

Answer:

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Step-by-step explanation:

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\text{Volume of hollow cylinder}=\pi R^2h-\pi r^2h

where,

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r = Radius of internal cylinder.

h = Height of cylinder.

substituting our given values in above formula, we will get:

\text{Volume of hollow cylinder}=\pi (5\text{ in})^2(\text{23 in})-\pi (4\text{ in})^2(\text{23 in})\text{Volume of hollow cylinder}=\text{23 in}\cdot 3.14 ((5\text{ in})^2-(4\text{ in})^2)\text{Volume of hollow cylinder}=\text{23 in}\cdot 3.14 (25\text{ in}^2-16\text{ in}^2)\text{Volume of hollow cylinder}=\text{23 in}\cdot 3.14 (9\text{ in}^2)\text{Volume of hollow cylinder}=649.98\text{ in}^3

Therefore, the volume of the pipe is 649.98 cubic inches.

8 0
3 years ago
The shaded region in the figure shows recommended weight and height combinations. Determine the recommended weight range for a p
vitfil [10]
5h - w = 170
for h = 77
w = 5h - 170
w = 5*77 - 170
w = 385 - 170
<span>w = 215

Shoutout to @himanshuchaturvedi 

Your answer is : w = 215 

Have an amazing day and stay hopeful!

</span>
8 0
3 years ago
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