Lines <em>a</em> and <em>b</em> are parallel, so lines <em>p</em>, <em>q</em>, and <em>t</em> are considered to be transversals. To solve this, you make use of the fact that alternate interior angles are equal, as are alternate exterior angles, as are corresponding angles. Of course any linear pair of angles is supplementary.
∠1 = 90° — corresponding angle to the right angle above it
∠2 = 68° — the sum of 22° and angles 1 and 2 is 180°
∠3 = 112° — supplementary to angle 2 (and the sum of 22° and 90°, opposite interior angles of the triangle)
∠4 = 112° — equal to angle 3
∠5 = 68° — equal to angle 2; supplementary to angle 4
∠6 = 56° — base angle of isosceles triangle with 68° at the apex; the complement of half that apex angle
∠7 = 124° — supplementary to the other base angle, which is equal to angle 6; also the sum of angles 5 and 6
∠8 = 124° — alternate interior angle with angle 7, hence its equal.
Answer:
The solution is -22
Step-by-step explanation:
<em>The solution of an equation is the value of the variable of the equation</em>
∵ -(4x - 3) = -7(9 + x)
→ Simplify each side
∵ -(4x) - -(3) = -7(9) + -7(x)
∴ (-4x) - (-3) = -63 + (-7x)
→ Remember (-)(-) = (+) and (-)(+) = (-)
∴ -4x + 3 = -63 - 7x
→ Add 7x to both sides
∴ -4x + 7x + 3 = -63 - 7x + 7x
∴ 3x + 3 = -63
→ Subtract 3 from both sides
∵ 3x + 3 - 3 = -63 - 3
∴ 3x = -66
→ Divide both sides by 3
∴ x = -22
∴ The solution is -22
Answer:
6,7
Step-by-step explanation:
the squre root of 41 is 6.403
Answer:
Just click an x on the graph for each number in the chart.
1/4 would have 4 x's
2/4 would have 2 x's
3/4 would have 1 x
1 would have 2 x's
According to my calculations, it would take approximately 3.4 (being in decimal form) pages PER minute or Just 3 minuets being rounded to the nearest tenth. If I am I correct please correct me. I used a calculator.
