D. Have the same number of valence electrons
I graphed it. First you choose a number that’s less than 29 and greater than 29 which I chose 0 and 100 but it didn’t let me show the whole picture
Answer:
6x-3=Y
Step-by-step explanation:
Multiply x to both sides then subtract the 3
Answer:
0(n)
Step-by-step explanation:
Result previous exercise:
procedure count(a1a2...an : string with n > 1)
i:=0
for k:=1 to n
if ak =1 then i:=i + I
return i
<em>Note</em><em>: If you use a different algorithm, then you could possible get different results. </em>
<u>SOLUTION </u>
There is only one part of the code that contains an operation (comparison), namely if a_k =1
This comparison is executed in every iteration of the for-loop
k can take on the values from 1 to n (for k:=I to n), thus k can take on n values.
Thus in total there are then n comparisons, while n is 0(n).
Answer:
4 miles per hour
Step-by-step explanation:
I took it on k-12
