Question

the velocity of s free fall object is given by v=√2gh where v is the velocity (m/s) g is acceleration due to gravity (m/s^2), and h is the distance (m) fallen. if the object hits the surface with a velocity of 30m/sec and on the Earth the acceleration is g=9.81 m/s^2 , determine the height from which the object was dropped.

Answer 1

Therefore 45.87 m from which the object was dropped.

Step-by-step explanation:

Given , the velocity of free fall object is given by $v = \sqrt{2gh}$ where v is the velocity (m/s) g is acceleration due to gravity (m/s²) and h is the the distance (m) fallen.

v = 30 m/s

g = 9.81 m/s²

$v = \sqrt{2gh}$

⇔v² = 2gh [ squaring both sides]

$\Leftrightarrow h =\frac{v^2}{2g}$

$\Leftrightarrow h =\frac{30^2}{2 \times 9.81}$

$\Leftrightarrow h = 45.87$

Therefore 45.87 m from which the object was dropped.