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Anna71 [15]
3 years ago
14

Byte pair encoding is a data encoding technique. The encoding algorithm looks for pairs of characters that appear in the string

more than once and replaces each instance of that pair with a corresponding character that does not appear in the string. The algorithm saves a list containing the mapping of character pairs to their corresponding replacement characters.
For example, the string "THIS_IS_THE_BEST_WISH" can be encoded as "%#_#_%E_BEST_W#H" by replacing all instances of "TH" with "%" and replacing all instances of "IS" with "#".
Which of the following statements about byte pair encoding is true?
A. Byte pair encoding is an example of a lossy transformation because it discards some of the data in the original string.
B. Byte pair encoding is an example of a lossy transformation because some pairs of characters are replaced by a single character.
C. Byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.
D. Byte pair encoding is an example of a lossless transformation because it can be used to transmit messages securely.
Computers and Technology
1 answer:
erica [24]3 years ago
8 0

Answer:

C. Byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.

Explanation:

Byte pair encoding is a form of encoding in which the most common pairs of consecutive bytes of data are replaced by a single byte which does not occur within the set of data.

For example, if we has a string ZZaaAb, it can be encoded if the pairs of string ZZ are replaced by X and the second pair by Y. So, our data now becomes XYAb.

To get our original data, that is decode it, we just replace the data with the keys X = ZZ and Y = aa thus allowing our original data to be restored.

Since our original string is restored without loss of data, it implies that <u>byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.</u>

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Ivenika [448]

Answer:

All the 3 statements are true.

Explanation:

1. The class methods and instance methods of one class may call the public class methods of another class using dot notation and referencing the name of the other class.

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6 0
3 years ago
Write a C++ program that reads students' names followed by their test scores. The program should output each students' name foll
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Answer:

#include<iostream>

#include<conio.h>

using namespace std;

struct studentdata{

char Fname[50];

char Lname[50];

int marks;

char grade;

};

main()

{

studentdata s[20];

for (int i=0; i<20;i++)

   {

cout<<"\nenter the First name of student";

cin>>s[i].Fname;

cout<<"\nenter the Last name of student";

cin>>s[i].Lname;

cout<<"\nenter the marks of student";

cin>>s[i].marks;

}  

 

for (int j=0;j<20;j++)

{

if (s[j].marks>90)

{

 s[j].grade ='A';

}

else if (s[j].marks>75 && s[j].marks<90)

{

   s[j].grade ='B';

}

else if (s[j].marks>60 && s[j].marks<75)

{

 s[j].grade ='C';

}

else

{

 s[j].grade ='F';

}

}

int highest=0;

int z=0;

for (int k=0;k<20; k++)  

{

if (highest<s[k].marks)

{

 highest = s[k].marks;

 z=k;

}

 

}

cout<<"\nStudents having highest marks"<<endl;

 

cout<<"Student Name"<< s[z].Fname<<s[z].Lname<<endl;

cout<<"Marks"<<s[z].marks<<endl;

cout<<"Grade"<<s[z].grade;

getch();  

}

Explanation:

This program is used to enter the information of 20 students that includes, their first name, last name and marks obtained out of 100.

The program will compute the grades of the students that may be A,B, C, and F. If marks are greater than 90, grade is A, If marks are greater than 75 and less than 90, grade is B. For Mark from 60 to 75 the grade is C and below 60 grade is F.

The program will further found the highest marks and than display the First name, last name, marks and grade of student who have highest marks.

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3 years ago
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