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stiks02 [169]
4 years ago
7

To enter a typed number into a cell, you press Tab or Backspace?​

Computers and Technology
2 answers:
muminat4 years ago
7 0

Answer:

bOTH

Explanation:

VashaNatasha [74]4 years ago
4 0

To enter a typed number into a cell, you should press tab.

Pressing tab will enter the number into the cell and move you on to the next cell. Pressing backspace will only remove the number, which is the opposite of entering the number into the cell.

Hope this helps! :)

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____ contain instructions for the OS for hardware devices, such as the keyboard, mouse, and video card, and are stored in the sy
AnnyKZ [126]

The Motherboard contains instructions for the OS for hardware devices, such as the keyboard, mouse, and video card, and are stored in the systemroot\Windows\System32\Drivers folder.

Learned this in middle school, your welcome ;)

3 0
4 years ago
In ____, data can move in both directions at the same time, such as with a telephone.
gtnhenbr [62]

The answer is d. full-duplex transmission. This communication setup allows for simultaneous transmit and receive for both parties. As signals are able to be transmitted at the same time two way for both parties, for both directions along the same data carrier medium.

4 0
3 years ago
Write a MIPS assembly language program that accomplishes the following tasks:The program will prompt the user to enter an intege
Svetlanka [38]

Answer:

Here's the code below

Explanation:

# All the comment will start with #

# MIPS is assembly language program.

# we store the all the data inside .data

.data:

k: .asciiz "Enter the kth value:\n"

.text

.globl main

li $s0, 0 # $s0 = 0

li $t0, 0 # $t0 = 0

la $n0, k # $n0 is kth value address

syscall # call print_string()

li $v0, 0 # $v0

syscall

move $n0, $v0 # $a0 = user input or "int n"

addi $sp, $sp, -4 # move the stack pointer down

sw $ra, 0 ($sp) # save the return address for main

jal fncheck # call fncheck(n);

fncheck:

beq $n, 0, fnfirst #if n==0 then fnfirst

beq $n, 0, fnfirst #if n==0 then fnfirst

ble $n0, 5, fnrec # if (n <=5) then 5

bge $n0, 5, fnjoke

#first function for n 0 and 1

fnfirst:

li $t0, 0 # initialize $t0 = 0

addi $t0, $t0, 20 # $t0 = 20

move $v0, $t0 # return 20

jr $ra

#function to execute 5*function1(n-2) + n;

fnrec:

sub $sp, $sp, 12 # store 3 registers

sw $ra, 0($sp) # $ra is the first register

sw $n0, 4($sp) # $n0 is the second register

addi $n0, $n0, -2 # $a0 = n - 2

jal function1

sw $v0, 8($sp) # store $v0, the 3rd register to be stored

lw $n0, 4($sp) # retrieve original value of n

lw $t0, 8($sp) # retrieve first function result (function1 (n-2))

mul $t0, $t0, 5 # $t0 = 5 * function1(n-2)

add $v0, $v0, $t0

lw $ra, 0($sp) # retrieve return address

addi $sp, $sp, 12

jr $ra

#function to print joke

fnjoke:

la "Joke section"

4 0
4 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
4 years ago
In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block bp
Sergio039 [100]

In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.

<h3>What are BPDU used for?</h3>

A bridge protocol data unit (BPDU) is known to be a kind of a data message that is known to be often  transmitted in a local area network to be able to know or find loops in that given network topologies.

Hence, in the case above, In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.

See full question below

. In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block BPDUs?

a. BPDU filter

b. BPDU guard

c. root guard

d. BPDU drop

Learn more about ports from

brainly.com/question/10097616

#SPJ1

6 0
2 years ago
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