Answer:
Cartier played 21.33 minutes more than Ryan.
Step-by-step explanation:
Total duration of the game played = 60 minutes
Part of the game played by Ryan =
of the game
Duration of game played by Ryan = ![\frac{1}{5} \textrm{of the total minutes} = \frac{1}{5}\times 60 =12\ minutes](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%20%5Ctextrm%7Bof%20the%20total%20minutes%7D%20%3D%20%5Cfrac%7B1%7D%7B5%7D%5Ctimes%2060%20%3D12%5C%20minutes)
Part of the game played by Cartier =
of the game
Duration of game played by Ryan = ![\frac{5}{9} \textrm{of the total minutes} = \frac{5}{9}\times 60 =\frac{100}{3}=33\frac{1}{3}\ minutes](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%20%5Ctextrm%7Bof%20the%20total%20minutes%7D%20%3D%20%5Cfrac%7B5%7D%7B9%7D%5Ctimes%2060%20%3D%5Cfrac%7B100%7D%7B3%7D%3D33%5Cfrac%7B1%7D%7B3%7D%5C%20minutes)
Difference between their duration =
or 21.33 minutes
So, Cartier played 21.33 minutes more than Ryan.
Step-by-step explanation:
Answer is 20% of 20 is 4
Answer is 50%of 40 is 20
Answer is 125% of 100 is 125
I hope it's helpful!
Based on the definition of an isosceles trapezoid, the measure of angle MQP in the figure shown is: m∠MQP = 73°.
<h3>What is an Isosceles Trapezoid?</h3>
An isosceles trapezoid has the following properties:
- It has two diagonals that are equal.
- It has a pair of opposite sides that are congruent and a pair of opposite sides that are parallel.
- Opposite angles in an isosceles trapezoid are supplementary.
The figure given is an isosceles trapezoid.
The measure of angle MNP is given as 107°.
Angle MQP and angle MNP are opposite angles.
Based on the properties of an isosceles trapezoid, we have:
m∠MQP + m∠MNP = 180
Substitute
m∠MQP + 107 = 180
m∠MQP = 180 - 107
m∠MQP = 73°
Learn more about the isosceles trapezoid on:
brainly.com/question/4758162
#SPJ1
ANSWER
![T.S.A=1960m^2](https://tex.z-dn.net/?f=T.S.A%3D1960m%5E2)
EXPLANATION
The diagram represents the net of a rectangular prism.
The dimensions are,
![l=42m](https://tex.z-dn.net/?f=l%3D42m)
![w = 14m](https://tex.z-dn.net/?f=w%20%3D%2014m)
and
![h = 7m](https://tex.z-dn.net/?f=h%20%3D%207m)
The total surface area of a rectangular prism is given by:
![T.S.A=2(lw + lh + wh)](https://tex.z-dn.net/?f=T.S.A%3D2%28lw%20%2B%20lh%20%2B%20wh%29)
We substitute the values to obtain,
![T.S.A=2(42 \times 14 + 42 \times 7 + 14 \times 7)](https://tex.z-dn.net/?f=T.S.A%3D2%2842%20%5Ctimes%2014%20%2B%2042%20%5Ctimes%207%20%2B%2014%20%5Ctimes%207%29)
![T.S.A=2(980)m^2](https://tex.z-dn.net/?f=T.S.A%3D2%28980%29m%5E2)