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Triss [41]
2 years ago
15

Suppose that a defined population is all left-handers, and a survey is being

Mathematics
1 answer:
Kryger [21]2 years ago
5 0

Answer: A

Step-by-step explanation:Greg

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Use the information to answer the following question.
trasher [3.6K]

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D is the answer

Step-by-step explanation:

For a: g(x) = 1 when x = 1, for f(x) 1^2 - 2(1) + 2 = 1, a is true.

For b: Both functions do have all real numbers for their domain, b is true

For c: the y-intercept of g(x) is x = 0, for f(x), it is 0^2 - 2(0) + 2 = 2, c is true

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2 years ago
Does the equation x2 - 6x + y2 - 6y = -9 intersect the y-axis
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6 0
3 years ago
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

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