Ask question

Ask question

All categories

Novosadov [1.4K]

3 years ago

6

A number m multipled by 4 is grater than 12

1 answer:

Keith_Richards [23]3 years ago

5 0

M * 4 > 12 would be the answer.

You might be interested in

Louis has three more quarters than dimes for a total of $1.80. What equation can you use to determine how many dimes,x, in his p

elixir [45]

0.10x + 0.25(x + 3) = 1.80

3 0

3 years ago

Read 2 more answers

The least common multiple of 20, 24, and 45 is _____.<br> a) 30<br> b) 180<br> c) 360<br> d) 21,600

MaRussiya [10]

C) 360
because they can all be multiplied to get 360
20 times 18 24 times 15 45 times 8

8 0

3 years ago

Read 2 more answers

vladimir2022 [97]

Answer: Decreased by 12 students

Step-by-step explanation:

40-28=12

7 0

3 years ago

Read 2 more answers

Naddik [55]

I can give you the answer only for the first question, but this one will definitely help you and bring you the points you need. The amount of tax that is paid on the computer is <span>0.08x, where </span>x is the original cost
and 8% is the tax rate. Hope you still need because that's really works.

3 0

3 years ago

Read 2 more answers

Angie and Kenny play online video games. Angie buys 1 software package and 2 months of game play. Kenny buys 1 software package

GalinKa [24]

Answer:

The cost of one month of game play is $12.

Step-by-step explanation:

We are given the following in the question:

Cost of software package = $30

Let y dollars be the cost of one month of game play.

Angie buys 1 software package and 2 months of game play.

Angie's cost =

$1(30) + 2y = 2y + 30$

Kenny buys 1 software package and 4 months of game play.

Kenny's cost =

$1(30) + 4y = 4y + 30$

Total cost = $132

Thus, we can write the equation:

$(2y+30)+(4y+30) = 132\\6y + 60 = 132\\6y = 132-60\\6y = 72\\\Rightarrow y = 12$

Thus, the cost of one month of game play is $12.

7 0

3 years ago