Answer: d=70; f=45; e=65
Step-by-step explanation:
NUMBER 1 WAY
110+d=180
d=70
135+f=180
f=45
d+f+e=180
70+45+e=180
e=65
--------------------------------------------------
NUMBER 2 WAY
concept to know: exterior angle theorem
------------------------------
System of equation
d+e=135
f+e=110
d+e+f=180
------------------------
d=135-e
f=110-e
-------------------------
d+e+f=180
(135-e)+e+(110-e)=180
135-e+e+110-e=180
245-e=180
e=65
-----------------------
d=70
e=65
f=45
To find the price of the treadmill, you can calculate the amount you will pay after each day and then multiply by the percentage that you will pay for each additional day.
You should use 85% (100% - 15%) as the part you will pay for a quicker calculation.
$4000 x 0.85 = $3400 (after the first day)
$3400 x 0.85 = $2890 (after the second day)
$2890 x 0.85 = $2456.50 (after third day)
<span>If the price of the treadmill yesterday was $4000, what will be the price of the treadmill 2 days from now? I interpreted this as the discount would be applied for 3 days.</span>
Answer:
3g+6
Step-by-step explanation:
6g+8-3g-2
combine like terms
6g-3g= 3g
3g+8-2
8-2= 6
3g+6
Answer:
<em>There is no significant difference in the amount of rain produced when seeding the clouds.</em>
Step-by-step explanation:
Assuming that the amount of rain delivered by thunderheads follows a distribution close to a normal one, we can formulate a hypothesis z-test:
<u>Null Hypothesis
</u>
: Average of the amount of rain delivered by thunderheads without seeding the clouds = 300 acrefeet.
<u>Alternative Hypothesis
</u>
: Average of the amount of rain delivered by thunderheads by seeding the clouds > 300 acrefeet.
This is a right-tailed test.
Our z-statistic is
We now compare this value with the z-critical for a 0.05 significance level. This is a value
such that the area under the Normal curve to the left of
is less than or equal to 0.05
We can find this value with tables, calculators or spreadsheets.
<em>In Excel or OpenOffice Calc use the function
</em>
<em>NORMSINV(0.95)
</em>
an we obtain a value of
= 1.645
Since 1.2845 is not greater than 1.645 we cannot reject the null, so the conclusion that can be drawn when the significance level is 0.05 is that there is no significant difference in the amount of rain produced when seeding the clouds.
The left hand side of the equation is a difference of two squares and may be factored out as follows,
(x - 4)(x + 4) > 0
They may be individually taken as,
x - 4 > 0 ; x > 4
x + 4 > 0 ; x < -4
Thus, the answer to this item is letter A.