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sdas [7]
3 years ago
15

Solve for p. i = prt p = i-rt p = (rt)/i p = i/(rt)

Mathematics
1 answer:
andrezito [222]3 years ago
6 0

Answer:

\sf p = \dfrac{i}{rt}

Step-by-step explanation:

Solve for p:

\longrightarrow i = prt

i = prt is equivalent to prt = i:

\longrightarrow prt = i

Divide both sides by rt:

\longrightarrow \sf \dfrac{prt}{rt} = \dfrac{i}{rt}

\sf \dfrac{prt}{rt} = p:

\longrightarrow \sf p = \dfrac{i}{rt}

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Find k if (x+1) 2x^3+kx^2+1
Viktor [21]
<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

k = 1

<h2>Step-by-step explanation:</h2>

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

<em>This is because;</em>

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ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

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Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

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3 years ago
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