The fewest number of days over which the tournament can take place is 5 days.
<h3>How to calculate the number of days?</h3>
As each team plays with other team Once and we have total 5 teams so number of matches will be (4+3+2+1)
Counted as team 1 plays with all other teams = 4 matches
Team 2 plays with team 3,4,5 =3 matches
Team 3 play with team 4,5=2 match
And the last match is between team 4 and team5
Total match = 10 and can be played two matches per day:
Number of days = 10/2
= 5 days.
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Answer:
-2x + 3 – (5 – 6x) = 4x - 2
Step-by-step explanation:
The given expression is :
-2x + 3 – (5 – 6x)
We need to simplify the above expression. First opening the brackets.
-2x + 3 – (5 – 6x) = -2x + 3 – 5 + 6x
Taking like terms together,
= -2x+6x + 3 -5
= 4x - 2
So, the simplified expression is 4x - 2.
Answer:divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.
Step-by-step explanation:
divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.
Answer:
a) scale factor = 1.5
b) d length is 7.5
c) Area scale factor is 2.25
Step-by-step explanation:
Given QR =6
And ST =9
Length Scalar factor = enlarged length /previous length
=9/6
=1.5
Length Scalar factor =1.5
b)we know PS enlarged length of PQ
Length scale factor = PS/PQ
1.5 =PS/5
PS =5×1.5
PS =d =7.5
d length is 7.5
c)Formula :
Area scale factor = (length scale factor)2
=(1.5)2
=2.25
Area scale factor is 2.25
Y=x+25 has the biggest increase so i think its B
