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Marat540 [252]
2 years ago
8

Craig solicited donations for his school's jump-rope-a-thon. He collected $13 in fixed donations and pledges totaling $2 for eac

h minute, m, he jumps rope at the event. The total amount of money Craig has raised is represented by the expression: 13 + 2m.
What is the total amount of money Craig will raise if he jumps rope for 18 minutes?
Mathematics
1 answer:
Nastasia [14]2 years ago
6 0

Answer:

Step-by-step explanation:

18x2

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What is closest to the total length of sex cars?
maks197457 [2]

Answer:

D) 32.5 ft

Step-by-step explanation:

Here we have to use the trigonometric ratio.

We need to find the length of the hypotenuse.

We use sin ratio.

Sin 38 = Opposite / Hypotenuse

Here opposite = 20, Hypotenuse = Length of the six cars

sin 38 = 20 / length of the six cars

The length of six cars = 20 / sin 38

The length of the six cars = 32.48

Which is closest to 32.5 ft

Thank you.

3 0
3 years ago
Read 2 more answers
Is this answer correct?
BabaBlast [244]
Yes the mean is the middle number so go according to the order from smallest to biggest 48 is the middle number
5 0
3 years ago
I am a parent, i am trying to put together some math notes for my son. He is allowed to use them for the unit 2 math test for 6t
yuradex [85]
Ok so what can we at Brainly do for you ?
5 0
3 years ago
Which complex number has a distance of √17 from the origin on the complex plane?
guapka [62]
Let the complex number be x + iy

Then by the pythagoras therem

17  = x^2 + y^2

D will satisfy this equation

4^2 + (-1)^2  = 17

answer is D  4 - i

6 0
3 years ago
Read 2 more answers
Separable differential equation <br> y’ln^2y+ysqrtx=0 y(0)=e
Maksim231197 [3]

By applying the theory of <em>separable ordinary differential</em> equations we conclude that the solution of the <em>differential</em> equation \frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0 with y(0) = e is y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}.

<h3>How to solve separable differential equation</h3>

In this question we must separate each variable on each side of the equivalence, integrate each side of the expression and find an <em>explicit</em> expression (y = f(x)) if possible.

\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0

(\ln y)^{2}\,dy =  -y \cdot \sqrt{x}\, dx

-\frac{(\ln y)^{2}}{y}\, dy = \sqrt{x} \,dx

-\int {\frac{(\ln y)^{2}}{y} } \, dy = \int {\sqrt{x}} \, dx

If u = ㏑ y and du = dy/y, then:

-\int {u^{2}\,du } = \int {x^{\frac{1}{2} }} \, dx

-\frac{1}{3}\cdot u^{3} = \frac{2\cdot x^{\frac{3}{2} }}{3} + C

u^{3} = -2\cdot x^{\frac{3}{2} } + C

(\ln y)^{3} = - 2\cdot x^{\frac{3}{2} } + C

C = (\ln e)^{3}

C = 1

And finally we get the <em>explicit</em> expression:

\ln y = \sqrt [3]{-2\cdot x^{\frac{3}{2} }+ 1}

y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}

By applying the theory of <em>separable ordinary differential</em> equations we conclude that the solution of the <em>differential</em> equation \frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0 with y(0) = e is y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}.

To learn more on ordinary differential equations: brainly.com/question/14620493

#SPJ1

6 0
2 years ago
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