Answer: B) [-0.0332,0.1332]
Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval where we can be a percentage sure the true mean is.
The confidence interval for a difference in population proportion is calculated following these steps:
First, let's find population proportion for each population:


Second, calculate standard deviation for each proportion:


Now, we calculate standard error for difference:


SE = 0.0505
The z-score for a 90% CI is 1.645.
Then, confidence interval is
± z-score.SE
± 
0.05 ± 0.0831
The limits of this interval are:
inferior: 0.05 - 0.0831 = 
superior: 0.05 + 0.0831 = 0.1332
The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is
.