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olga_2 [115]
3 years ago
13

Explain how to estimate 498÷12

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0
498 is approximately 500

12 is approximately 10



500/10 = 50



So, 498/12 is approximately 50.
exis [7]3 years ago
8 0
Round 498 to the hundreds place making it 500. Then round the twelve to a 10 because you have to follow the rule that if the digit you are rounding is below five you go back if it is above five you round to the next place. The problem would then become 500/10 which is equal to 50
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Four years ago Ravi was 8 years older than Priya. If he is now 3times as old as she is, find their present ages?
GenaCL600 [577]

Answer:

24

Step-by-step explanation:

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4 0
3 years ago
It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportat
katrin2010 [14]

Answer: H_0:\mu=120

H_A:\mu\neq120

Step-by-step explanation:

Let \mu denotes the average braking distance for a population of small car.

Given : It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet.

i.e. \mu=120

Objective of test : Whether the statement made in the advertisement is false

i.e.  \mu\neq120

Since '=' signs is contained by Null hypothesis and alternative hypothesis is against it.

So the null and the alternative hypotheses for the test will be:

H_0:\mu=120

H_A:\mu\neq120

4 0
3 years ago
Bacteria triples every hour. How much bacteria will there be after two days if they started with 13,000 bacteria.
timofeeve [1]
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Hope this helps!
6 0
2 years ago
Can you please help me
Igoryamba

Answer:

30 inches

Step-by-step explanation:

8 0
2 years ago
Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
2 years ago
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