Question

8. In a population of beetles, there is a gene for color with two codominant alleles. The allele R leads to red beetles and the allele B leads to blue beetles. Heterozygous beetles are red and blue spotted. A heterozygous beetle mates with a red beetle. What is are the genotypic and phenotypic frequencies of their offspring? Please show all of your work. (2)

Answer 1

Answer:

The genotypic frequency = 1:1

The phenotypic frequency = 1:1

Explanation:

Given that:

The allele → R = Red beetles

The allele → B = Blue beetles

Since the gene color shows a codominant allele

The Red Beetle = RR

The blue beetles will be = BB

The heterozygous beetle will be = RB

∴

The punnet square showing the crossing of RB × RR is:

                R                   B

R                RR               RB

R                RR               RB

The result shows that we have two red beetles and two heterozygous beetles.

Hence;

The genotypic frequency = 1:1

The phenotypic frequency = 1:1