When sohring the equation, which is the best first step to begin to simplify the equation?

A bookstore manager marks down the price of older hardcover books,which originally sell for b dollars,by 46 percent. What is the

baherus [9]

46 percent as a decimal is 0.46

b-0.46b=p
b is original price
p is price after markdown

6 0

4 years ago

Is | 4x + 2| + 6 = 0 no solution, all real numbers, 0, or 2

Arisa [49]

Subtract 6 from each side. Then you have an absolute value equal to -6. But an absolute value is never negative. So there is no solution.

8 0

3 years ago

A new born baby has about 26,000,000,000 cells. An adult has about 4.94 × 10^13 cells. How many times as many cells does an adul

anzhelika [568]

4.94*10^13 / 2.6*10^10=1.9 * 10^3=1900 times

5 0

3 years ago

Are most student government leaders extroverts? According to Myers-Briggs estimates, about 82% of college student government lea

nataly862011 [7]

Answer:

$z=-1.12$

$p_v =2*P(z$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we don't have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the population proportion of extroverts among college student government leaders is not different from 0.82.

Step-by-step explanation:

1) Data given and notation

n=74 represent the random sample taken

X=57 represent the number of people found extroverts

$\hat p=\frac{57}{74}=0.770$ estimated proportion of people found extroverts.

$p_o=0.82$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.959

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test if population proportion of extroverts among college student government leaders is different (either way) from 82%, the system of hypothesis would be on this case:

Null hypothesis: $p= 0.82$

Alternative hypothesis: $p \neq 0.82$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.770 -0.82}{\sqrt{\frac{0.82(1-0.82)}{74}}}=-1.12$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we don't have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the population proportion of extroverts among college student government leaders is not different from 0.82.

4 0

3 years ago

How can tell before you divide 387 by 4, that the first digit of the quotient in in the tens place?

iVinArrow [24]

You can tell before you divide 387 by 4, that the first digit of the qoutient is going to be in tens place, because 3 can't go into 4.

7 0

4 years ago