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4 years ago

14

The table below gives the list price and the number of bids received for five randomly selected Items sold through online auctio

ns. Using this data, consider the equation of the regression line hat y =b 0 +b 1 x for predicting the number of bids an item will receive based on the list price. Keep in mind
, the correlation coefficient may or may not be statistically significant for the data givenRemember, practice , it would not be appropriate to use the regression line to make a prediction the correlation coefficient is not statistically significant Price in Dollars 39 40 42 43 45 Number of Bids 1 3 5 6 8 Table Copy Data Step 1 of 6: Find the estimated slope: Round your answer to three decimal places

Advanced Placement (AP)

2 answers:

kobusy [5.1K]4 years ago

3 0

Answer:

14 birds

Explanation:

julsineya [31]4 years ago

3 0

14 birds is the answer

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mafiozo [28]

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$r = 5.24$ --- Radius

$h = 10.48$ --- Height

Explanation:

Given

Object: Can (Cylinder)

$Surface\ Area = 517.8cm^2$

Required

Maximize the volume

The surface area is:

$S.A = 2\pi r^2 + 2\pi rh$

Substitute 517.8 for S.A

$517.8 = 2\pi r^2 + 2\pi rh$

Divide through by 2

$258.9 = \pi r^2 + \pi rh$

Factorize:

$258.9 = \pi r(r + h)$

Divide through by $\pi r$

$\frac{258.9}{\pi r} = r + h$

Make h the subject

$h = \frac{258.9}{\pi r} - r$ --- (1)

Volume (V) is calculated as:

$V = \pi r^2h$

Substitute (1) for h

$V = \pi r^2(\frac{258.9}{\pi r} - r)$

Open Bracket

$V = 258.9r - \pi r^3$

Differentiate V

$V' = 258.9 - 3\pi r^2$

Set V' to 0

$0 = 258.9 - 3\pi r^2$

Collect Like Terms

$3\pi r^2 = 258.9$

Divide through by 3

$\pi r^2 = 86.3$

Divide through by $\pi$

$r^2 = \frac{86.3}{\pi}$

$r^2 = \frac{86.3*7}{22}$

$r^2 = \frac{604.1}{22}$

Take square root of both sides

$r = \sqrt{\frac{604.1}{22}$

$r = 5.24$

Recall that:

$h = \frac{258.9}{\pi r} - r$

Substitute 5.24 for r

$h = \frac{258.9}{\pi * 5.24} - 5.24$

$h = \frac{258.9*7}{22 * 5.24} - 5.24$

$h = \frac{1812.3}{115.28} - 5.24$

$h = 15.72 - 5.24$

$h = 10.48$

Hence, the dimension that maximize the volume is:

$r = 5.24$ --- Radius

$h = 10.48$ --- Height

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