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3 years ago

12

Hannah and Jayna have disposable cameras . The table and descriptions show the number of shots left on their cameras as a functi

on of time.

2 answers:

Gelneren [198K]3 years ago

7 0

Answer: Both functions have a negative rate of change.

Step-by-step explanation:

The numbers are decreasing. And I just got it right.

Shkiper50 [21]3 years ago

6 0

Answer: the answer is is both functions have a negative rate of change

Step-by-step explanation:

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मिनधन १.. 18,900 हुन्छ भन सावा रकम पता लगा

Vladimir [108]

Answer:

Solution given:

principal [P]=P

time [T]=4 years

Rate [R]=13%

compound amount=18900

Simple interest=P-18900

we have

simple interest= $\frac{P*T*R}{100}$

P-18900= $\frac{P*4*13}{100}$

100P-1890000=52P

48P=1890000

P=1890000/48

P=39375

the sum that amounts =Rs 39375

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3 years ago

PLEASE HELP ILL GIVE MEDALS AND MARK BRAINLIEST !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Effectus [21]

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3 years ago

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natka813 [3]

Answer:

A

Step-by-step explanation:

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3 years ago

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The circumference of a circle

Dmitry_Shevchenko [17]

Use the formula C = pi * d

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4 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago