Show that if p(a) ⊂ p(b) then a ⊂ b.
<span>I will assume p() means power set. </span>
<span>proof: let x∈a, then {x} ∈ p(a) and so by hypothesis {x} ∈ p(b). However {x} could not be in p(b) unless x∈b. This shows that each element of a is an element of b and hence a ⊂ b.
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Answer:
-3a-4b+5
Step-by-step explanation:
(3a-6b+12)-(6a-2b+7)
3a-6b+12-6a+2b-7
3a-6a-6b+2b+12-7
-3a-4b+5
A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.
F(1) = 240 +210
F(2) = 240 +2(210)
F(3) = 240+3(210)
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F(x)= 240 +210x.
Learn more about Sequence:
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Answer:

Step-by-step explanation:
Simply plug in 10 for <em>n</em>
9(1/3)¹⁰⁻¹
9(1/3)⁹
9(1/19683)
9/19683
