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Firdavs [7]
3 years ago
8

What is the perpendicular slope of m= -3/2

Mathematics
1 answer:
zhenek [66]3 years ago
8 0

Answer:

-2/3

Step-by-step explanation:

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How do I find the inverse of this problem?
raketka [301]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Inverse of real function.

Let's consider here, g(n) = y ,

so we get as,

y =  \sqrt[3]{ \frac{n - 1}{2} }

no, cubing the power both side we get as,

=>

{y}^{3}  =  \frac{n - 1}{2}

now,

2 {y}^{3}  = n - 1

so finally, we get as,

=>

n = 2 {y}^{3}  + 1

hence,here, n = inverse of the g(n) function.

so,

g^-1 (n) = 2y^3+1.

7 0
2 years ago
The Polar Express
Igoryamba

Answer:

for 12-8: 33.33

or

for 8-4: 50

or

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Step-by-step explanation:

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2 years ago
Determine the equation of the line that passes through (2,4) with a slope of -2/3
DedPeter [7]

Answer:

y = -2/3x + 16/3

Step-by-step explanation:

y = -2/3x + b

4 = -2/3(2) + b

4 = -4/3 + b

16/3 = b

4 0
3 years ago
The coefficient of 2(3)(6)Q is
Alik [6]

Answer:

36Q

Step-by-step explanation:

multiply all together we have 36Q

5 0
1 year ago
6cos(20πt-π)+6√3cos(20πt-π\2)
juin [17]

Answer:

<u>Answer</u><u> </u><u>is</u><u> </u><u>-</u><u>6</u><u>t</u>

Step-by-step explanation:

{ \tt{ = (6 \cos(20\pi t)  \cos(\pi)  +  6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t)  \cos( \frac{\pi}{2} )  +  \sin(20\pi t)   \sin( \frac{\pi}{2} )) }} \\  = { \tt{ (- 6t + 0) + (0 + 0)}} \\  = { \tt{ - 6t}}

Note that π is 180°

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2 years ago
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