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bearhunter [10]
2 years ago
13

PLEASE HELP!!!! I NEED HELP BADLY!!

Mathematics
1 answer:
MaRussiya [10]2 years ago
4 0
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What is the function rule of (1,30) (2,35) (3,40) (4,45)?
stepan [7]
\bf \begin{array}{ccll}
x&y\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&30\\
2&35\\
3&40\\
4&45\\
a&5(a)+25
\end{array}\qquad \qquad y=5x+25

if you have already covered slopes, you could also get it that way, in fact is  simpler that way.
8 0
3 years ago
(SHOW UR WORK I DONT FEEL LIKE DOING THIS XDD BUT THANKSS) 98.73 ÷ 15 =
Juliette [100K]

Answer:

Answer 6.582

Step-by-step explanation:

   0 6. 5 8 2

1 5 9 8. 7 3 0

 − 0        

   9 8      

 − 9 0      

     8 7    

   − 7 5    

     1 2 3  

   − 1 2 0  

         3 0

       − 3 0

           0

Hope its understandable ._.

5 0
2 years ago
SOMEONE HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
n200080 [17]
To find the amount of solutions, you must find the discriminant. The discriminant is b^2 - 4ac. Number 6 has 2 solutions and number 7 has 1 solution.
6 0
2 years ago
Read 2 more answers
The volume of a rectangular prism is 57 cubic inches. What is the volume of a
BARSIC [14]

Answer:I'd sayb

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The diagram shows the sector of a circle with the centre O and radius 6cm.
cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = \frac{\theta}{360}(\pi r^{2})

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = \frac{50}{360}(\pi )(6)^2

                                  = 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = \frac{1}{2}(OP)(PN)

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = \frac{PN}{ON}

PN = ONsin(25°)

     = 6sin(25°)

     = 2.536 cm²

cos(25°) = \frac{OP}{ON}

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

                         = 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

                                             ≈ 1.92 cm²

3 0
2 years ago
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