Let's solve for h.
h
p
=
p
3
+
4
p
2
−
2
Step 1: Divide both sides by p.
h
p
p
=
p
3
+
4
p
2
−
2
p
h
=
p
3
+
4
p
2
−
2
p
Answer:
h
=
p
3
+
4
p
2
−
2
p
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.
to find the least common multiple, you need to first figure out what the prime factors have in common.

each have two twos. both have one 5, so we know our answer will look something like

now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.
one has one 3 and one has two, so we need two threes. now our equation is

what's the only number we have to deal with? 7...
how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
First change the 1/2 to eighths. multiply numerator and denominator by 4.now subtract 4 1/8
Putting the other player's king in check is always a good move. true
<h3>What is chess?</h3>
- The policies of chess allow a king to take an opponent's piece whilst in check, so long as that piece isn't always being defended.
- At the equal time, a king in the test is usually forced to move.
- The standard regulations of chess, a participant may not make any pass that places or leaves their king in the test.
- A player may additionally pass the king, seize the threatening piece, or block the check with some other piece.
- A king cannot look at the opposing king, considering this will vicinity the first king in check as well.
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