The answer is
<span>x+1</span>, <span>x+2</span>, <span>x+3</span>, <span>x+4</span> and <span>x+5</span>.
The sum of these six integers is 393 so we can write:
<span>x+x+1+x+2+x+3+x+4+x+5=393</span>
<span>6x+1+2+3+4+5=393</span>
<span>6x+15=393</span>
<span>6x+15−15=393−15</span>
<span>6x+0=378</span>
<span><span><span>6x</span>6</span>=<span>3786</span></span>
<span>x=63</span>
Because the first integer is 63 then the third would be <span>x+2</span> or <span>63+2=<span>65</span></span>
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<span><span>Hope its helps :)</span></span>
X= # tickets Tom sold
3x+16= # tickets Steve sold
Add the amounts Tom and Steve sold and that will equal 104 total tickets sold.
x+(3x+16)=104
4x+16=104
Subtract both sides by 16
4x=88
Divide both sides by 4
x=22 # tickets Tom sold
Substitute the x=22 answer to find Steve's tickets sold
3x+16= 3(22)+16= 82 # tickets Steve sold
Hope this helps! :)
There are several ways,
One, which is easiest, is to divide them, if the result is greater than 1, then the fraction at the numerator is larger. If the answer is less than 1, then the fraction at the denominator is larger.
Another way, is to try making both fractions have the same denominator and compare; the one with greater numerator is the larger fraction.
Hope this helps!
-18+3(5x-2)+8
-18+15x-6+8
-24+15x+8
-16+15x
I hope this helps
Answer:
its 55
Step-by-step explanation:
you minus 125 from 180 to get 55
