Answer:
see below
Step-by-step explanation:
For simplifying expressions of this sort, there are four rules of exponents that come into play;
![a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}](https://tex.z-dn.net/?f=a%5Eba%5Ec%3Da%5E%7Bb%2Bc%7D%5C%5C%5C%5C%28ab%29%5Ec%3Da%5Ecb%5Ec%5C%5C%5C%5C%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7Ba%5Eb%7D%3Da%5E%7B-b%7D%5C%20%5Cquad%5Ctext%7Bwhich%20means%7D%5Cquad%20a%5Eb%3D%5Cdfrac%7B1%7D%7Ba%5E%7B-b%7D%7D)
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I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.
![23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9](https://tex.z-dn.net/?f=23.%20%5Cquad%5Cdfrac%7B1%7D%7Bx%5E%7B-2%7D%7D%3Dx%5E2%5C%5C%5C%5C24.%20%5Cquad%5Cdfrac%7Bmn%7D%7Bm%5E2n%5E3%7D%3Dm%5E%7B1-2%7Dn%5E%7B1-3%7D%3Dm%5E%7B-1%7Dn%5E%7B-2%7D%3D%5Cdfrac%7B1%7D%7Bmn%5E2%7D%5C%5C%5C%5C25.%20%5Cquad%5Cdfrac%7Bk%5E%7B-2%7D%7D%7Bk%5E%7B-3%7D%7D%3Dk%5E%7B-2-%28-3%29%7D%3Dk%5C%5C%5C%5C26.%20%5Cquad%5Cleft%28%5Cdfrac%7Bm%5E2%7D%7Bn%5E3%7D%5Cright%29%5E3%3D%5Cdfrac%7Bm%5E%7B2%5Ccdot%203%7D%7D%7Bn%5E%7B3%5Ccdot%203%7D%7D%3D%5Cdfrac%7Bm%5E6%7D%7Bn%5E9%7D%5C%5C%5C%5C27.%20%5Cquad%5Cdfrac%7Bx%5E2y%5E3z%5E4%7D%7Bx%5E%7B-3%7Dy%5E%7B-4%7Dz%5E%7B-5%7D%7D%3Dx%5E%7B2-%28-3%29%7Dy%5E%7B3-%28-4%29%7Dz%5E%7B4-%28-5%29%7D%3Dx%5E5y%5E7z%5E9)
A snowflake falls 90 feet in 1 minute.
60 ÷ 4 = 15
6 x 15 = 90
Let the number of rows be = r
Let the number of seats per row be = s
we know that the number of seats is 126.
So,
..... (1)
As given, there are five more seats per row than the number of rows, so we can say that:
![s=r+5](https://tex.z-dn.net/?f=s%3Dr%2B5)
Putting this in equation (1)
![(r+5)*r=126](https://tex.z-dn.net/?f=%28r%2B5%29%2Ar%3D126)
![r^{2}+5r=126](https://tex.z-dn.net/?f=r%5E%7B2%7D%2B5r%3D126)
![r^{2}+5r-126=0](https://tex.z-dn.net/?f=r%5E%7B2%7D%2B5r-126%3D0)
![r^{2}+14r-9r-126=0](https://tex.z-dn.net/?f=r%5E%7B2%7D%2B14r-9r-126%3D0)
![(r+14)(r-9)=0](https://tex.z-dn.net/?f=%28r%2B14%29%28r-9%29%3D0)
r=-14 and r=9 (neglecting the negative value) we get r=9
And s=r+5
so, s =9+5=14
Hence, there are 5 rows and 14 seats per row.
9514 1404 393
Answer:
375 hamburgers
Step-by-step explanation:
Let h represent the number of hamburgers. Then h+63 is the number of cheeseburgers, and the combined total is ...
h +(h +63) = 813
2h = 813 -63 = 750
h = 750/2 = 375
375 hamburgers were sold on Saturday.
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<em>Additional comment</em>
In a "sum and difference" problem like this, the smaller number is half the difference between the sum and the difference. h = (813 -63)/2 = 375. This generic solution applies to all "sum and difference" problems.