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3 years ago

All of the following are equal except a)-|5| b)-|-5| c)|-5| d) the opposite of 5

2 answers:

8 0

The answer is C. Having a value inside the absolute value bars will make the number positive (|-14| = 14, |6| = 6), but it doesn’t affect the operations outside of it. A,B, and D are all -5, while C is 5.

goldenfox [79]3 years ago

5 0

I’m pretty sure the answer is C

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100% is 75 oranges what percent is 250 oranges?

Whitepunk [10]

Answer:

x=333.33%

Step-by-step explanation:

hello

you can resolve this by using the rule of 3,let´s see

75 oranges =100%

250 oranges = x%?

75 oranges* x%=250 oranges *100%

$x=\frac{250*100}{75}$

x=333.33%

Have a great day.

4 0

3 years ago

Classwork for Ms. O'Brien's (Root X

alexandr1967 [171]

Answer:

4673 mm²

Step-by-step explanation:

base: 51.7 mm

height: 90.39 mm

iPhone's screen is a rectangle. The area of rectangle is calculated as base*height. Replacing with data we get:

Area of rectangle = area of the iPhone's screen = 51.7 mm * 90.39 mm = 4673.163 mm² ≈ 4673 mm²

7 0

3 years ago

83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi

arlik [135]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

Step-by-step explanation:

Information given

$\bar X=32.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom given by:

$df=n-1=8-1=7$

The confidence level is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.