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3 years ago

PLEASE HELP - System of equations matrix prepresents

Mathematics

1 answer:

Sever21 [200]3 years ago

6 0

9514 1404 393

Answer:

the marked choice is the correct one

Step-by-step explanation:

A suitable calculator or web app can reduce this matrix for you.

The solution is represented by the matrix ...

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-1\\0&0&1&3\end{array}\right]$

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Cheyenne ran a 6.36-kilometer race in 53 minutes. What was her speed in kilometers per hour?

svlad2 [7]

Answer:

7.23km/h

Step-by-step explanation:

Speed = distance/time

Given

distance = 6.36km and

Time = 53minutes

Convert 53minutes to hour.

60 minutes = 1 hour

53 minutes = x hour

Cross multiply

X hour x 60 = 53

Xhour = 53/60

X = 0.88 hour

Therefore

Speed = 6.36km /0.88hr

= 7.23km/h

5 0

4 years ago

Read 2 more answers

How much larger than 3/4 is 25/32

kvv77 [185]

First change the denominator to the same denominator so you can easily compare them.

3/4= 24/32. The difference between them is 1/24, or 25/32 is larger than 3/4 by 1/24.

Hope this helped.

8 0

3 years ago

How do i do this?? plz help

babunello [35]

Answer: 0.142

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

PLEASE HELP!! WILL GIVE BRAINLIEST

yarga [219]

Answer:

The graphs shown is NOT a function.

Step-by-step explanation:

We can use Vertical Line test to determine whether a given relation in the graph is a function or not. A relation is a function if one input results in only one output. If we draw vertical lines on the graph, and any of these vertical line intersect the graph at 2 or more positions, then it means that for one value of x, there are 2 values of y. Hence, for one input, there are more than one outputs. Therefore, the relation will not be a function.

We can see in the attached graph below that any vertical line intersects the graph at 2 positions. Hence, the given relation is graph is not a function.

Apologies for the rough drawing.

You can apply the same technique for the graph of the relation which is not shown, you'll get your answers to fill in the blanks

6 0

4 years ago

I need help solving x^2+3xy-y^2=12 and x^2-y^2=-12

Georgia [21]

$substitute:x^2-y^2=-12\ to\ x^2+3xy-y^2=12\\\\3xy-12=12\\3xy=12+12\\3xy=24\ \ \ \ \ /:3\\xy=8\to x=\frac{8}{y}\\\\substitute\ to\ x^2-y^2=-12\\\\\left(\frac{8}{y}\right)^2-y^2=-12\\\\\frac{64}{y^2}=y^2-12$

$\frac{64}{y^2}=\frac{y^2-12}{1}\\\\y^2(y^2-12)=64\\\\y^4-12y^2-64=0\\\\substitute:y^2=t > 0\\\\t^2-12t-64=0$

$a=1;\ b=-12;\ c=-64\\\Delta=b^2-4ac\to\Delta=(-12)^2-4\cdot1\cdot(-64)=144+256=400\\\\t_1=\frac{-b-\sqrt\Delta}{2a};\ t_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{400}=20\\\\t_1=\frac{12-20}{2\cdot1}=\frac{-8}{2}=-4 < 0;\ t_2=\frac{12+20}{2\cdot1}=\frac{32}{2}=16\\\\y^2=16\Rightarrow y=\pm\sqrt{16}\Rightarrow y=-4\ or\ y=4\\\\x=\frac{8}{-4}=-2\ or\ x=\frac{8}{4}=2\\\\Solution:x=-2\ and\ y=-4\ or\ x=2\ and\ y=4$

3 0

3 years ago