If you're good at logarithms please help me with question two d and h thanks
1 answer:
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Answer:
The equation in slope-intercept form will be:
- y = -2x + 14
Step-by-step explanation:
Given
- slope = m = -2
- point (5, 4)
We know that the slope-intercept form of the line equation is
where m is the slope of the line and b is the y-intercept
substituting m = -2 and the point (5, 4) in the slope-intercept form to get the y-intercept 'b'
y = mx+b
4 = -2(5) + b
4 = -10 + b
b = 4+10
b = 14
now substituting m = -2 and b = 14 in the slope-intercept form to get the equation in slope-intercept
y = mx+b
y = -2x + 14
Therefore, the equation in slope-intercept form will be:
- y = -2x + 14
Hi there!
We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):
Taking the derivative gets:
Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):
0 = -8/x³ - 2
2 = -8/x³
2x³ = -8
x³ = -4
Another critical point is also where the graph has an asymptote (undefined), so at x = 0.
Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:
f'(1) = -8/1 - 2 = -10 < 0
f'(-1) = -8/(-1) - 2 = 6 > 0
f'(-2) = -8/-8 - 2 = -1 < 0
Thus, the values of x are: