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Elena-2011 [213]
2 years ago
8

Factors of polynomial 3xsquare +x-4

Mathematics
2 answers:
Alex73 [517]2 years ago
6 0

Answer:

(x - 1)(3x + 4)

Step-by-step explanation:

Given

3x² + x - 4

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 4 = -12 and sum = + 1

The factors are - 3 and + 4

Use these factors to split the x- term

3x² - 3x + 4x - 4 ( factor the first/second and third/fourth terms )

= 3x(x - 1) + 4(x - 1) ← factor out (x - 1) from each term

= (x - 1)(3x + 4) ← in factored form

Dennis_Churaev [7]2 years ago
4 0

Answer:

(3x + 4)(x - 1)

Step-by-step explanation:

3x^2 + x - 4

use middle term break method

we need two number which gives 12 when multiplied and 1 when subtracted

3x^2 + (4 - 3)x - 4

3x^2 + 4x - 3x - 4

x(3x + 4) -1(3x + 4)

(3x + 4)(x - 1)

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Yes because you only need a 90 degree to become a right
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taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

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<span>   Σ (2i + 3)
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@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
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When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
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Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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The correct answer is a.

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Not sure whether it's too late to help you though!!!!

Also notice that it's kind of a product rule:

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