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Elena-2011 [213]
2 years ago
8

Factors of polynomial 3xsquare +x-4

Mathematics
2 answers:
Alex73 [517]2 years ago
6 0

Answer:

(x - 1)(3x + 4)

Step-by-step explanation:

Given

3x² + x - 4

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 4 = -12 and sum = + 1

The factors are - 3 and + 4

Use these factors to split the x- term

3x² - 3x + 4x - 4 ( factor the first/second and third/fourth terms )

= 3x(x - 1) + 4(x - 1) ← factor out (x - 1) from each term

= (x - 1)(3x + 4) ← in factored form

Dennis_Churaev [7]2 years ago
4 0

Answer:

(3x + 4)(x - 1)

Step-by-step explanation:

3x^2 + x - 4

use middle term break method

we need two number which gives 12 when multiplied and 1 when subtracted

3x^2 + (4 - 3)x - 4

3x^2 + 4x - 3x - 4

x(3x + 4) -1(3x + 4)

(3x + 4)(x - 1)

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serg [7]

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2 years ago
the coordinates of the vertices of a rectangle in order are (5,2), (-1,4), (-2,1) and (4,-1). what is the perimeter of the recta
Anna [14]

Answer:

19 units

Step-by-step explanation:

Plot points  A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units

The perimeter of the rectangle ABCD is

AB+BC+CD+DA=2\sqrt{10}+\sqrt{10}+2\sqrt{10}+\sqrt{10}=6\sqrt{10}\approx 18.97\ units\approx 19\ units

3 0
3 years ago
Olsjsissjshsjsjsjsh help
stellarik [79]

Answer:

If u really struggle with maths u could use an application names photomath cuz it really helped me. Sry I can't help but I think photomath will be helpful

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3 years ago
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A student claims that the rectangular point below can be represented by the
Sladkaya [172]

Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number.  I like writing polar coordinates with a P in front to remind me.

It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.

P(6√2, 7π/4) = ( 6√2 cos 7π/4, 6√2 sin 7π/4 )

P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )

That's true since when we add pi to an angle it negates both the sine and the cosine,

cos(7π/4) = cos(π + 3π/4) = -cos(3π/4)

sin(7π/4) = sin(π + 3π/4) = -sin(3π/4)

Answer: TRUE

3 0
3 years ago
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