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3 years ago

I need help to figure out x.

Mathematics

2 answers:

lesantik [10]3 years ago

4 0

X would be 7 because you set 11x - 2 equal to 75 degrees (11x - 2 = 75), add 2 to both sides (11x - 2 + 2 = 75 + 2) to get 11x = 77, then divide both sides by 11 (11x / 11 = 77 / 11) to get x = 7

balu736 [363]3 years ago

3 0

Because the angles are congruent, they'll have same measure of angle. They would both be 75°. The equation for this situation would be
75=11x-2
77=11x
7=x

x is 7

You might be interested in

If I currently have a 77% in my course, and I have final that's worth 30%, how would a score of exactly 0% or 100% on the final

Neporo4naja [7]

Answer:

If you score a 0% on your exam, you get 53.9% as your overall grade
If you score 100% on your exam, you get 83.9% as your overall grade

====================================================

Explanation:

Your final is worth 30% of your grade, so the other 70% is what you've already done so far

The expression below

0.30x + 0.70*0.77

represents what your final grade would be in decimal form. We multiply the weights 0.30 and 0.70 with each of their corresponding grade value.

The x represents the decimal form of the final exam score.

------------

Let's say you get a 0% on the final. That would mean x = 0 and

0.30x + 0.70*0.77

0.30*0 + 0.70*0.77

0.539

So you'd end up with a 53.9% as the overall grade.

------------

Now let's say you get 100% on the final. We plug in x = 1 since it's the decimal form of 100%

So,

0.30x + 0.70*0.77

0.30*1 + 0.70*0.77

0.839

You would end up with a 83.9% as the overall grade.

4 0

3 years ago

The curves r1(t) = 2t, t2, t4 and r2(t) = sin t, sin 5t, 2t intersect at the origin. Find their angle of intersection, θ, correc

masya89 [10]

Answer:

Therefore the angle of intersection is $\theta =79.48^\circ$

Step-by-step explanation:

Angle at the intersection point of two carve is the angle of the tangents at that point.

Given,

$r_1(t)=(2t,t^2,t^4)$

and $r_2(t)=(sin t , sin5t, 2t)$

To find the tangent of a carve , we have to differentiate the carve.

$r'_1(t)=(2,2t,4t^3)$

The tangent at (0,0,0) is [ since the intersection point is (0,0,0)]

$r'_1(0)=(2,0,0)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{2^2+0^2+0^2} =2$

Again,

$r'_2(t)=(cos t ,5 cos5t, 2)$

The tangent at (0,0,0) is

$r'_2(0)=(1 ,5, 2)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{1^2+5^2+2^2} =\sqrt{30}$

If θ is angle between tangent, then

$cos \theta =\frac{r'_1(0).r'_2(0)}{|r'_1(0)|.|r'_2(0)|}$

$\Rightarrow cos \theta =\frac{(2,0,0).(1,5,2)}{2.\sqrt{30} }$

$\Rightarrow cos \theta =\frac{2}{2\sqrt{30} }$

$\Rightarrow cos \theta =\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =cos^{-1}\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =79.48^\circ$

Therefore the angle of intersection is $\theta =79.48^\circ$ .

8 0

3 years ago

The surface area of a cube is represented by the expression below, where s is the side length of the cube. Find the surface area

Dmitry [639]

Answer:

486 centimeters³

Step-by-step explanation:

Surface area of a cube = 6s²

Where,

s = side length

Find the surface area of a cube-shaped jewelry gift box with a side length of 9 centimeters.

s = 9 centimeters

Surface area of a cube = 6s²

= 6 × 9²

= 6 × 81

= 486 centimeters³

Surface area of a cube-shaped jewelry gift box with a side length of 9 centimeters 486 centimeters³

8 0

2 years ago

Where can I find about slopes in homework 5 unit 3

chubhunter [2.5K]

Answer:

idk

Step-by-step explanation: sorry im in unit 6 in science im working on rn

baiiii

4 0

3 years ago

A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.

kenny6666 [7]

Answer:

$p:y = 3x-10$

Step-by-step explanation:

We are given the following in the question:

A(1, 1), B(2, 4), C(4, 2)

i) Slope of AB

$A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3$

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

$y - y_1 = m(x - x_1)$

The point intercept form of line can be written as:

$y = mx + c$

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

$y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10$

which is the required slope intercept equation of line p.

4 0

3 years ago