Answer:
STEP
1
:
12
Simplify ——
1
Equation at the end of step
1
:
-15 k 5
(((————)+((8•—)•k))-————————-10k)+(12•k2))-5k)-12
(k2) 2 (k3)(k2)
STEP
2
:
Equation at the end of step 2
-15 k 5
(((————)+((8•—)•k))-————————-10k)+(22•3k2))-5k)-12
(k2) 2 (k3)(k2)
STEP
3
:
Equation at the end of step
3
:
-15 k 5
(((————)+((8•—)•k))-——————-10k)+(22•3k2))-5k)-12
(k2) 2 (k3)k2
STEP
4
:
5
Simplify ——
k3
Equation at the end of step
4
:
-15 k 5
(((————)+((8•—)•k))-————-10k)+(22•3k2))-5k)-12
(k2) 2 k3k2
STEP
5
:
k
Simplify —
2
Equation at the end of step
5
:
-15 k 5
(((————)+((8•—)•k))-————-10k)+(22•3k2))-5k)-12
(k2) 2 k3k2
STEP
6
:
15
Simplify ——
k2
Equation at the end of step
6
:
15 5
(((——)+4k2)-————-10k)+(22•3k2))-5k)-12
k2 k3k2
I don't have popsicle but I'm sure you will melt by this answer.
Hope this helps. (please don't melt)
r3t40
Given that a person's normal body temperature is 98.6 ° F, and according to physicians, a person's body temperature should not be more than 0.5 ° F from the normal temperature, to determine how you could use an absolute value inequality to represent the temperatures that fall outside of normal range, the following logical-mathematical reasoning must be carried out:
As long as the normal temperature is 98.6 ° F, and its variation should not be greater than 0.5 ° F in its increase or decrease, it is correct to say that the range of normal body temperatures is equal to 98.6 - 0.5 to 98.6 + 0.5, that is, it has a variability that goes from 98.1 ° F to 99.1 ° F.
Thus, the absolute value inequality of 0.5 (both subtracting and adding) determines the limits of the temperature parameter considered normal.
Learn more in brainly.com/question/4688732
Answer:
-4 cot (-45)
Step-by-step explanation:
cos (390)
sin (330)
