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3 years ago

14

The price of a computer was $ 375. In a sale, the price was reduced by 15%. Calculate the reduction in the price of the computer

.

2 answers:

Bingel [31]3 years ago

8 0

Answer:

$ 56.25

Step-by-step explanation:

Reduction = 15% of 375

$= \frac{15}{100}*375\\\\= 0.15*375\\= $56.25$

Advocard [28]3 years ago

4 0

Answer:

318.75

Step-by-step explanation:

15% of 375 is 56.25. then you just subtract 56.25 from 375 and get 318.75

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4 years ago

A communications company has developed three new designs for a cell phone. To evaluate consumer response, a sample of n = 120 co

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Answer:

The answer is "Its results are not consistent with its three designs Yes. Its results show significant differences between both the three designs."

Step-by-step explanation:

Following are the distribution of preference:

$Design 1 =54 \\\\ Design 2=38 \\\\\ Design 3=28 \\\\$

$Design \ \ \ \ \ \ \ \ \ \ O_i \\ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 54 \\2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 38\\3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 28 \\Total \ \ \ \ \ \ \ \ \ \ 120$

An expected frequency( $E_i$ ) has 40 Null hypotheses to take n=120.to each design:

The effects of the three designs are standardized

Inaccurate.

Hypothesis Alternative:

The effects of the three prototypes are not uniform

Degrees Of freedom $=(n-1)=(3-1)=2$

$H_o, x^2 \ test\ statistic \ \sum_i {\frac{(O_i -E_i)^2}{E_i}} \\$

$= \frac{(54 -40)^2}{40}+\frac{(38-40)^2}{40} + \frac{(28-40)^2}{40}\\\\=49+0.1+3.6\\\\=8.6$

Chi-squared distribution critical value at $\alpha = 0.05 (x^2 _{0.052})=5.99$

Since $x^2, a$ value $> x^2 -$ table of $\alpha =0.05 =5.99$ is determined.

So $H_o$ is rejected.

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3 years ago