Answer:
the groups’ historical connections to Mound Builders.
the arrival of European explorers and settlers.
their shared language and culture.
their shared geography and climate.
Explanation:
It's been asked before, here's the source: brainly.com/question/1617622
Answer:
The Jumanos were a tribe or several tribes, who inhabited a large area of western Texas, adjacent New Mexico, and northern Mexico, especially near the Junta de los Rios region with its large settled Indian population. Spanish explorers first recorded encounters with the Jumano in 1581; later expeditions noted them in a broad area of the Southwest and the Great Plains. The last historic reference was in a 19th-century oral history, but their population had declined by the early 18th century.[1]
Scholars have generally argued that the Jumanos disappeared as a distinct people by 1750 due to infectious disease, the slave trade, and warfare, with remnants absorbed by the Apache or Comanche, but as of 2008, self-identified Apache-Jumano (Jumano Ndé - “Red Mud Painted People”) in southwest Texas, an amalgam of mostly Jumano, but also Comanche and Apachean groups (with close ties to Mescalero Apache and Lipan Apache) currently have 300 members with up to 3000 more claimed. They hope to be recognized as an official tribe.
Explanation:
hope this helps
(a)
<span>Let: </span>
<span>a be the acceleration of the system, </span>
<span>g be the acceleration due to gravity, </span>
<span>T be the tension in the string. </span>
<span>For mA: </span>
<span>T = mA a </span>
<span>For mB: </span>
<span>mB g - T = mB a </span>
<span>Adding to eliminate T: </span>
<span>mB g = (mA + mB)a ...(1) </span>
<span>a = mB g / (mA + mB) </span>
<span>= 7.0 * 9.81 / (11.0 + 7.0) </span>
<span>= 3.815 m/s^2 </span>
<span>= 3.82 m/s^2 to 3 sig. fig. </span>
<span>(b) </span>
<span>Let: </span>
<span>s be the distance to the edge of the table, </span>
<span>t be the time taken. </span>
<span>s = at^2 / 2 </span>
<span>t = sqrt(2s / a) </span>
<span>= sqrt(2 * 1.250 / 3.815) </span>
<span>= 0.810 sec to 3 sig. fig. </span>
<span>(c) </span>
<span>From (1): </span>
<span>(mA + mB)(a / g) = mB </span>
<span>mA(a / g) = mB(1 - a / g) </span>
<span>mA = mB(g / a - 1) </span>
<span>= 4.0(100 - 1) </span>
<span>= 396 kg.</span>
<span>6,000 visitors , i think.</span>