Answer:
x = -7 2/3, y = 1 1/3 and z = 5 1/3.
Step-by-step explanation:
2x+4y+3z=6 ..... 1
x-2y+z=-5 ...... 2
-x-3y-2z=-7 .......3
Add equations 2 and 3 to eliminate x:
-5y - z = -12 .....4
Multiply equation 2 by - 2:
-2x + 4y - 2z = 10
Add this to equation 1:
8y + z = 16 ........ 5
Now add equation 4 to equation 5:
3y = 4
y = 4/3 = 1 1/3.
Now find z by substituting for y in equation 4:
-5(4/3) - z = -12
z = 12 - 20/3
z = 36/3 - 20/3 = 16/3 = 5 1/3.
Finally, we find x by substituting for y and z in equation 1:
2x + 4*4/3 + 3*16/3 = 6
2x = 6 - 16/3 - 16
2x = 18/3 - 16/3 - 48/3 = -46/3
x = 23/3 = 7 2/3.
I got 6 and -7 when I did this problem, maybe you made a mistake or maybe I did. But you are on the right track
Answer:
measure of ∠ABD = 42°
Step-by-step explanation:
Angle Formed by Tangent and Secant = (1/2)*(difference of Intercepted Arcs)
In this case the intercepted arcs are: minor arc AC and minor arc AD. Let´s first find minor arc AD, we know that:
minor arc AC + minor arc CD + minor arc AD = 360°
Then,
minor arc AD = 360° - minor arc AC - minor arc CD
minor arc AD = 360° - 72° - 132°
minor arc AD = 156°
Replacing in the aforementioned formula:
Angle Formed by Tangent and Secant = (1/2)*(difference of Intercepted Arcs)
∠ABD = (1/2)*(minor arc AD - minor arc AC)
∠ABD = (1/2)*(156° - 72°)
∠ABD = 42°
I hope this helps you
A ) 7 less than triple a number
B ) 7 more than triple a number
C ) 3 less than seven time a number
D ) 3 more than seven time a number
answer is B
Answer:
Step-by-step explanation:
Given:
Original price of the ticket is 
Price after using the coupon is 
Coupon discount is 85% of 
Therefore, the price after applying coupon is given as the difference of the original price and the coupon discount. That is,
The graph is shown below. The graph passes through the origin as the above relationship is a proportional relationship.
The line strictly remains in the first quadrant as both and can't be negative as they represent price of tickets and price can never have negative values. Hence, only the first quadrant has both the values of and positive.
