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brilliants [131]
3 years ago
8

How do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat p

ears how do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat pears how do I eat pears
Mathematics
2 answers:
UkoKoshka [18]3 years ago
3 0

Answer: first open your mouth then hold the pear and put it inn your mouth then chew then it will go down your thought

Step-by-step explanation:

Butoxors [25]3 years ago
3 0

Answer:

k

Step-by-step explanation:

k

You might be interested in
One scientific team determened that the avrage thickness of a chickens egg shell is 0.311 millimeters
rosijanka [135]

Answer:

As we can see the average for the thickness of a chickens egg shell is 0.311 mm and if we want to round this number to the nearest tenth we just need to see the second decimal place and round to one decimal place.

This second decimal place for this number is 1 and this number is \leq 5 so then if we round to the nesrest tenth we will get:

0.3 mm

Step-by-step explanation:

We use the following info in order to complete the qeustion:

Round the thickness of the shell to the nearest tenth.

0.3

0.5

0.92

9

As we can see the average for the thickness of a chickens egg shell is 0.311 mm and if we want to round this number to the nearest tenth we just need to see the second decimal place and round to one decimal place.

This second decimal place for this number is 1 and this number is \leq 5 so then if we round to the nesrest tenth we will get:

0.3 mm

7 0
3 years ago
Can someone answer my newest question please will give brainly
Aleksandr-060686 [28]

Answer:

yes if you give me brainliest

Step-by-step explanation:

8 0
3 years ago
How to solve and answer please.
jek_recluse [69]

Answer:

sin 77°

cos 49°

tan 22°

Step-by-step explanation:

use your calculator with trig functions to find the arcsin, arccos, and arctan

7 0
3 years ago
1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.
m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = \frac{9}{7+9}\times (x)

                                      = \frac{9}{16}\times (x)

And the weight of zinc = \frac{7}{7+9}\times (x)

                                      = \frac{7}{16}\times (x)

If the weight of zinc = 31.5 kg

31.5 = \frac{7}{16}\times (x)

x = \frac{16\times 31.5}{7}

x = 72 kgs

Therefore, weight of copper = \frac{9}{16}\times (72)

                                               = 40.5 kgs

2). i). 2 : 3 = \frac{2}{3}

        4 : 5 = \frac{4}{5}

Now we will equalize the denominators of each fraction to compare the ratios.

\frac{2}{3}\times \frac{5}{5} = \frac{10}{15}

\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}

Since, \frac{12}{15}>\frac{10}{15}

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = \frac{11}{19}

    19 : 21 = \frac{19}{21}

By equalizing denominators of the given fractions,

\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}

And \frac{19}{21}\times \frac{19}{19}=\frac{361}{399}

Since, \frac{361}{399}>\frac{231}{399}

Therefore, 19 : 21 > 11 : 19

iii). \frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}

             =\frac{3}{2}

     \frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}

              = \frac{4}{3}

Now we equalize the denominators of the fractions,

\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}

And \frac{4}{3}\times \frac{2}{2}=\frac{8}{6}

Since \frac{9}{6}>\frac{8}{6}

Therefore, \frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4} will be the answer.

IV). 1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}

                  =\frac{6}{5}\times \frac{3}{4}

                  =\frac{18}{20}

                  =\frac{9}{10}

Similarly, \frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}

                       =\frac{4}{15}                  

By equalizing the denominators,

\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}

Similarly, \frac{4}{15}\times \frac{20}{20}=\frac{80}{300}

Since \frac{270}{300}>\frac{80}{300}

Therefore, 1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}

V). If a : b = 6 : 5

     \frac{a}{b}=\frac{6}{5}

        =\frac{6}{5}\times \frac{2}{2}

        =\frac{12}{10}

  And b : c = 10 : 9

  \frac{b}{c}=\frac{10}{9}

 Since a : b = 12 : 10

 And b : c = 10 : 9

 Since b = 10 is common in both the ratios,

 Therefore, combined form of the ratios will be,

 a : b : c = 12 : 10 : 9

7 0
3 years ago
A cellular family phone plan cost $49 per minute plus five cents per minute of long distance service. Write an equation for the
miskamm [114]

The equation for monthly payment is b = 49.05M.

<u>SOLUTION:</u>

Given, a cellular family phone plan cost $49 per minute plus five cents per minute of long distance service. We have to write an equation for the monthly payment b when M minutes of long distance service are used.

Now, given that,

\begin{array}{l}{\text { Monthly payment = } \$ 49 \text { per minute plus five cents per minute of long distance }} \\\\ {\Rightarrow \$ 49 \times \text { number of minutes }+\$ 0.05 \times \text { number of minutes of long distance }} \\\\ {\Rightarrow \mathrm{b}=49 \times \mathrm{M}+0.05 \times \mathrm{M} \rightarrow \mathrm{b}=49 \mathrm{M}+0.05 \mathrm{M} \rightarrow \mathrm{b}=49.05 \mathrm{M}}\end{array}

<em>Equation:</em>

An equation is a statement that the values of two mathematical expressions are equal <em>(indicated by the sign =)</em>

5 0
4 years ago
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