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2 years ago

How do you find the inverse of a function on a graph

Mathematics

1 answer:

Yanka [14]2 years ago

7 0

Answer:

visual wise: you mirror it

Step-by-step explanation:

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F(x)=2x and g(x)=square root of x what is the domain of f(g(x))?

Dmitriy789 [7]

Answer:

$x\ge 0$

Step-by-step explanation:

The given functions are:

$f(x)=2x$

and

$g(x)=\sqrt{x}$

Now,

$f(g(x))=f(\sqrt{x} )$

$f(g(x))=2\sqrt{x}$

The domain refers to values of $x$ for which $f(g(x))=2\sqrt{x}$ is defined.

The expression under the radical sign must not be negative.

The domain is

$x\ge 0$

5 0

2 years ago

Find the surface area of the cylinder to the nearest tenth of a square unit. use 3.14 for pi

Alborosie

Given:

Height of cylinder is 18.2 cm
Radius of cylinder is 3 cm

$~$

To Find?

Surface area

$~$

Solution:

Using formula:

Surface area of cylinder = 2πr (h + r)

$~$

Substituting values in the formula:

$\longrightarrow \sf 2 × 3.14 × 3 (18.2 + 3)$

$\longrightarrow \sf 6.28 × 3 (21.2)$

$\longrightarrow \sf 18.84 × 21.2$

$\longrightarrow \sf 399.4 cm²$

$~$

Hence, (B) 399.4 cm² is right answer.

6 0

2 years ago

If y = 3x - 4 and the domain is {-3,-1,4}, find the range.

GREYUIT [131]

We could put the domain into the x values to get the y values (range).

y = 3(-3) - 4
y = -9 - 4
y = -13

y = 3(-1) - 4
y = -3 - 4
y = -7

y = 3(4) - 4
y = 12 - 4
y = 8

4 0

3 years ago

Read 2 more answers

Using Cavalieri's Principle, what is the general formula for the volume of a cone?

Anit [1.1K]

Answer:

The volume for a cone and pyramid are the same, V = 1/3 Bh where B is the area of the base.

Step-by-step explanation:

So even though the base is a different shape, as long as the areas and heights are the same, they will have the same volume.

4 0

2 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$