
We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
Answer:
Component form : (-7 , 2)
Step-by-step explanation:
P(4 , 5) = P'(4 +x , 5+y) = P'(-3 , 7)
4 + x = -3
x = -3 - 4
x = -7
5 + y = 7
y = 7 - 5
y = 2
Vector form : -7i + 2j
Component form : (-7 , 2)
Answer:
12,300%
Step-by-step explanation:
I think it is 60 years old?