In parallelogram HJKL if m∡HJK=110∘ find m∡JKL.
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Answer: t = 6 s
Step-by-step explanation:
When Rose hit the water, the height of the jump is 0, so: h(t) = 0.
Resolving it, we have:
-16t² + 16t + 480 = 0
To simplify the second degree equation, divided it by 16:
-t² + t + 30 = 0
Now, solve the equation using Bhaskara:
Δ = 1² - 4. (-1) . 30
Δ = 1 + 120
Δ = 121
t =
t₁ = = - 5
t₂ = = 6
Since time can be negative, it took t = 6s for Rose to hit the water.