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Alina [70]
3 years ago
6

What is the answer for 16% of 150

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0
16% of 150
.16x150=24
liubo4ka [24]3 years ago
3 0
Make an equation: x= 16% x 50 x= 16 50 ---- x ---- Cross Multiply 100 1 x= 16 ------ = 8
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Answer:

a) \bar X = 121.4

b) SE = \frac{\sigma}{\sqrt{n}}= \frac{15}{\sqrt{40}}=2.372

c) 121.4-1.64\frac{15}{\sqrt{40}}=117.51    

121.4+1.64\frac{15}{\sqrt{40}}=125.29  

Step-by-step explanation:

Data given: 126,111,141,96,123,115,116,113,127,114,122,116,104,126,126,132,139,111,143,121,119,107,154,125,120,135,142,132,94,103,143,115,132,107,118,105,101,135,94,153

Part a

For this case we can calculate the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And after replace we got:

\bar X = 121.4

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

For this case we assume that the population deviation is \sigma=15, we can calculate the standard error with this formula:

SE = \frac{\sigma}{\sqrt{n}}= \frac{15}{\sqrt{40}}=2.372

Part c

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

121.4-1.64\frac{15}{\sqrt{40}}=117.51    

121.4+1.64\frac{15}{\sqrt{40}}=125.29  

8 0
3 years ago
Read 2 more answers
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