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Rus_ich [418]
2 years ago
12

Solve for t -t=9(t-10) t=

Mathematics
2 answers:
n200080 [17]2 years ago
8 0
-t=9(t-10)
-t=9t-90
90=9t+t
90=10t
90/10=t
9=t
castortr0y [4]2 years ago
6 0

Final Answer: t = 9

Steps/Reasons/Explanation:

Question: Solve for t. -t=9(t-10).

<u>Step 1</u>: Expand.

-t = 9t - 90

<u>Step 2</u>: Subtract 9t from both sides.

-t - 9t = -90

<u>Step 3</u>: Simplify -t - 9t to -10t.

-10t = -90

<u>Step 4</u>: Divide both sides by -10.

t = \frac{-90}{-10}

<u>Step 5</u>: Two negatives make a positive.

t = \frac{90}{10}

<u>Step 6</u>: Simplify \frac{90}{10} to 9.

t = 9

~I hope I helped you :)~

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=============================================

Work Shown:

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Write the equation in vertex form and then find the vertex, focus, and directrix of a parabola with equation x=y^2+18y-2
kakasveta [241]

Answer:

Part 1) The vertex is the point (-83,-9)

Part 2) The focus is the point (-82.75,-9)

Part 3) The directrix is x=-83.25

Step-by-step explanation:

step 1

Find the vertex

we know that

The equation of a horizontal parabola in the standard form is equal to

(y - k)^{2}=4p(x - h)

where

p≠ 0.

(h,k) is the vertex

(h + p, k) is the focus

x=h-p is the directrix

In this problem we have

x=y^{2} +18y-2

Convert to standard form

x+2=y^{2} +18y

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so

This is a horizontal parabola open to the right

(h,k) is the point (-83,-9)

so

The vertex is the point (-83,-9)

step 2

we have

x+83=(y+9)^{2}

<em>Find the value of p</em>

4p=1

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<em>Find the focus</em>

(h + p, k) is the focus

substitute

(-83+1/4,-9)

The focus is the point (-82.75,-9)

step 3

Find the directrix

The directrix of a horizontal parabola is

x=h-p

substitute

x=-83-1/4

x=-83.25

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3 years ago
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