Answer:
[2,3] is the answer
assuming you didn't have equal symbols under the inequality signs, you know
and
.
Step-by-step explanation:
Ok let's solve 3x+4>13 or 1/2 x+3<4.
Let's begin with 3x+4>13.
3x+4>13
Subtract 4 on both sides:
3x>9
Divide both sides by 3:
x>3
Now the other 1/2 x +3<4.
Subtract 3 on both sides:
1/2 x<1
Multiply both sides by 2:
x<2
So we have x>3 or x<2
If we graph this, this will give us better idea of what is and isn't a solution.
~~~~~~~~O x<2
O~~~~~~ x>3
------------(2)---------(3)---------
The only numbers not included are between 2 and 3 (inclusive).
So if x is between [2,3] then A or B has no solution.
Answer:


Step-by-step explanation:
Given
x = First Number
y = Second Number
Required
Write a system of equations
<u>Sum is 84</u>
This is represented as:

<u>Square of first is 6 more than the second</u>
This is represented as:

Hence, the equations are:


Answer:
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one
<em>For the graph below, what should the domain be so that the function is at least 200? graph of y equals minus 2 times the square of x plus 30 times x plus 200
</em>
My answer:
Given the above information, we have:
To make the function is at least 200, it means that:
≥ 200
<=>
≥ 0
<=> x(-2x+30) ≥ 0
This is the product of two numbers hence would be positive only if either both are positive or both are negative
x ≥ 0 and (-2x+30) ≥ 0
<=> 0 ≤ x ≤ 15
Then we get

This is inconsistent as a value cannot be less than 0 and greater than 15
=> our correct answer is
Hope it will find you well.
something is wrong with your question bc 690 plus 575 equals to 1265
SNKRS watch Poseidon last by laughably Lance