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balu736 [363]
3 years ago
9

Matthew has a bag that contains orange chews, cherry chews, and lime chews. He

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Answer: 13/24

Step-by-step explanation:

The experiment occurred 24 times orange or lime was selected 10+3=13

Probability the next chew will be orange or lime: 13/24

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Emily folded a paper circle into 2 equal parts. What is the angle measure of each part?​
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The diameter splits the circle into 2 equal halves by going through the midpoint of the circle. The two halves are called semicircles.
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4 years ago
All of the following are equivalent except _____.
lianna [129]

Answer:

-5(x - 1)

Step-by-step explanation:

you would get -5x - 5 if you solved it

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4 years ago
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Louie is trying to find a rectangular canvas for his art project. Its height
Maru [420]

The length of the diagonal of the canvas is approximately 27 degrees.

The height of the rectangular canvas must reach 18 inches. It must form a 48 degrees angle with the diagonal at the top of the canvas.

<h3>Length of the diagonal Canvas</h3>

Therefore, the length of the diagonal can be found as follows:

Using trigonometric ratio,

  • cos ∅ = adjacent / hypotenuse

where

∅ = 48°

adjacent side = Height of the rectangle = 18 inches

hypotenuse = Length of the diagonal

Therefore,

cos 48° = 18 / h

cross multiply

h = 18 / cos 48°

h = 18 / 0.66913060635

h = 26.9005778976

length of the diagonal ≈ 27 inches

learn more on rectangle here: brainly.com/question/26099609?referrer=searchResults

8 0
3 years ago
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
4 years ago
I know this question is easy, but I don’t really know how to do it? Help? If possible put a quick explanation, it’s fine if not!
lorasvet [3.4K]

Answer:

She left $10.62 the total was $58.87

Hope this helps :)

3 0
3 years ago
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