So the question is
number times 2/3 is greater than or less than the sasme number
so let's say x
x times 2/3 is greater than or less than x
since 2/3 is less than 1, 2/3 is a fraction,
anything times a fraction will become smaller
therefor
3 and 5/8 times 2/3 is less than 3 and 5/8
the answer is LESS THAN
Set up the equation so m<HCB + m<DCH = m<DCB
2x + 100 + 60 = x + 170
2x+ 160 = x +170
-x -x
x + 160 = 170
- 160 -160
x = 10
Found this. Hope it helps.
https://www.algebra.com/algebra/homework/word/coins/Word_Problems_With_Coins.faq.question.1059726.html
Answer:
(a) no solution
Step-by-step explanation:
Writing the second equation in slope-intercept form, it becomes ...
3x -y = 2 . . . . given
y = 3x -2 . . . . add y-2 to both sides
The first equation is already in slope-intercept form:
y = 3x +3 . . . . first equation
The coefficients of x in the two equations are both 3, so the lines they describe are parallel. They do not intersect, so there is <em>no solution</em>.
