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galben [10]
4 years ago
12

HELP PLEASE find the solution to the system of equations

Mathematics
1 answer:
ivanzaharov [21]4 years ago
4 0
(-2,0) is your answer:)))
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Eighth grade math. Please leave explanation!
kolbaska11 [484]

First multiply both sides by 7

Your equation now looks like this:

x-28=0

Now move the constant to the other side causing it to change signs

The negative now becomes a positive

x=28

Now you are left with your answer:

x=28

Hope this helps! :3

5 0
3 years ago
Read 2 more answers
Which statements about right triangles and hexagons are true?
Goryan [66]

Hello :) = Merhaba :)

Answer:

<h3><u><em>A and C</em></u></h3>

Step-by-step explanation:

Let's look at the chances:

A) Both shapes are polygons.

This answer is true. Because the triangle and the hexagon are polygons.

B) The first shape has the same number of sides as the second shape.

This answer is false. Because three sides of the triangle have six edges of the hexagon.

C) Both shapes have all sides of equal length.

This answer is true. Because the smooth polygons have equal edges.

NOTE: I'm not American. I'm just a Turk who wants to help you. So if my sentences are wrong, please forgive me.

<em><u>#Cevapistevereyim</u></em>

Başarılar :) = Achievements :)

8 0
3 years ago
Please solve these questions<br>​
olchik [2.2K]
A. 5
b. 2
c. 4
d. -2
e. 9
3 0
3 years ago
On each of 3 days, Derrick rode 6.45 km to school, 150 meters to the library, and then 500 meters back home. how many kilometers
Svetradugi [14.3K]

Answer: 21.3 km

Step-by-step explanation:

Given: On each of 3 days the distance traveled by Derrick to school = 6.45 km

The distance rode by Derrick to library = 150 meters

Since, 1 m=\frac{1}{1000}\ km

Thus, the distance rode by Derrick to library = 150\times\frac{1}{1000}\ km=0.15\ km

The distance rode by Derrick to home = 500 meters.

Thus, the distance rode by Derrick to home = 500\times\frac{1}{1000}\ km=0.5\ km

Distance he rode in each day = 6.45+0.15+0.5=7.1\ km

Now, Distance he rode in 3 days = 3\times7.1=21.3\ km

6 0
3 years ago
Read 2 more answers
The weights of rats in a city are normally distributed with a mean of 2.5 pounds and a standard deviation of 0.5 pounds.
alina1380 [7]
About 95%  of rats weight is between 2.5+2 *standard deviation=2.5+2*0.5=2.5+1=3.5 and 2.5-1=1.5 (1.5,3.5).
About 68% of rats weight is between (2.5-1*standard deviation, 2.5+1*standard deviation), (2,3).

This means that about 68 percent of rats in the city weigh between 2 pounds and 3 pounds. (solution b)
5 0
3 years ago
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