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oksian1 [2.3K]
3 years ago
12

How do I solve these two complex fraction problems?

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
7 0
Try the app Photomath!:)
Y_Kistochka [10]3 years ago
7 0
Maybe try the app slader that will help u for sure x
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Which letter is in the solution set for graph #2
stealth61 [152]

Answer:

<h2>A</h2>

Step-by-step explanation:

y > 0 - the region above the line together with that line

y ≥ 0 - the region above the line together with that line

y < 0 - the region below the line without that line

y ≤ 0 - the region below the line together with that line

We have:

y > 2 - the region above the line together with that line

y ≥ 2x - 3 - the region above the line together with that line

<em>look at the picture</em>

The common part is the solution.

8 0
3 years ago
A piece of cardboard measures 10 ft by 10 ft. Four equal squares of size x are removed from the corners. After removing the squa
Gnesinka [82]

Answer:

The value of x would be \frac{5}{3}

Step-by-step explanation:

Given,

The dimension of the cardboard = 10 ft by 10 ft,

∵ After removing four equal squares of size x ( in ft ) from the corners,

The dimension of the resultant box would be,

Length = ( 10 - 2x ) ft,

Width = ( 10 - 2x ) ft,

Height = x ft,

The volume of box,

V=(10-2x)\times (10 - 2x)\times x=x(10-2x)^2 = x(100 - 40x + 4x^2)=100x - 40x^2 + 4x^3

Differentiating with respect to x,

V'=100 - 80x + 12x^2

Again differentiating with respect to x,

V''=-80 + 24x

For maxima or minima,

V'=0

\implies 100 - 80x + 12x^2 = 0

\implies 3x^2 - 20x + 25=0

By quadratic formula,

x=\frac{20\pm \sqrt{20^2-4\times 3\times 25}}{6}

x=\frac{20\pm \sqrt{400 - 300}}{6}

x=\frac{20\pm \sqrt{100}}{6}

x=\frac{20\pm 10}{6}

\implies x = \frac{10}{6}=\frac{5}{3}\text{ or } x = 5

For x = 5/3, V'' = negative,

While for x = 5, V'' = Positive,

Hence, the value of x would be 5/3 ft for maximising the volume.

8 0
4 years ago
Is figure B a scaled copy of figure A
artcher [175]

No

We know scale factor(k)=y/x

Calculate units as 1 and find k

For left side

\\ \sf\longmapsto k=\dfrac{5}{3}

  • For base

\\ \sf\longmapsto k=\dfrac{4}{4}=1

Hence its not a copy

4 0
3 years ago
Read 2 more answers
The monomial of the 2nd degree with a coeficcient of 3
uranmaximum [27]
I assume it is the last one, 3n^2, because the degree is the exponent, which is two and the three is the coefficient, which is next to the variable, plus it is a monomial, so there is only one term, eliminating the first two, the third one is just reversed. Therefore, the answer should be the last one. Hope this helps. :)
4 0
3 years ago
Read 2 more answers
Bru how i do these 2 ?
Stells [14]
Use the pythagoream theorem A^2+B^2 then square your answer a being your adjacent side and b being your opposite leg.
7 0
2 years ago
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