In order to solve an equation for a certain variable, you should isolate that variable on one side of the equation and leave all the other terms on the other side on the equation.
The, you solve to get the value of the variable.
The equation we have here is:
<span>18−2x=4x
First, we need to isolate the terms containing the "x" on one side of the equation. To do this, we will add 2x to both sides of the equation:
</span><span>18−2x+2x=4x+2x
18 = 6x
Now, we need to get the value of the "x". To do this, we will simply divide both sides of the equation by 6:
18/6 = 6x/6
3 = x .............> This is the solution of the equation</span>
Answer:
I am pretty sure its the first one
1. Angle PAB is 90 degrees, as it is formed from the tanget to the circle at A, and the radius drawn to A.
2. AB=BC, because tangents drawn to a circle from the same point are equal.
3. PB is Common, so by the side-side-side congruence postulate, triangles ABP and CBP are congruent.
4. So measure of m(BPA)=x/2 and m(ABP)=73/2.
5.
, x= 107 degrees.
<h2><u>
Answer With Explanation:</u></h2>
<u>Firstly, let's start with <XOZ: =55°</u>
We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)
<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>
These 2 angles are joined to create an equilateral triangle which always adds up to 180°
So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°
<u>Thirdly, <QON: =55°</u>
This angle lies on the line XON which needs to add up to 180°
As we worked out before, <XOZ was 55°
So, <ZOQ was already given as 70°
We then do 55+70=125 then 180-125=55°
<QON is 55°
(I'm only in Grade 9 LOL)
