Given:
Five points P, Q, R, S ,T on a coordinate plane.
To find:
The coordinates of (i) P, (ii) Q, (iii) T, (iv) (Ordinate of T) – (Abscissa of R) and (v) (Abscissa of Q) – (Ordinate of S).
Solution:
From the given graph it is clear that the coordinates of given points are
P = (1,1)
Q = (-3,0)
R = (-2,-3)
S = (2,1)
T = (4,-2)
(i)
Coordinates of point P are (1,1).
Therefore, the correct option is (a).
(ii)
Coordinates of point Q are (-3,0).
Therefore, the correct option is (b).
(iii)
Coordinates of point T are (4,-2).
Therefore, the correct option is (c).
(iv)
Ordinate is y-coordinate and abscissa is x-coordinate.
Ordinate of T = -2
Abscissa of R = -2
(Ordinate of T) – (Abscissa of R) = -2 - (-2)
= -2 + 2
= 0
Therefore, the correct option is (c).
(v)
Abscissa of Q = -3
Ordinate of S = 1
(Abscissa of Q) – (Ordinate of S) = -3 - 1
= -4
Therefore, the correct option is (a).
