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miss Akunina [59]
2 years ago
11

Can someone help me with my algebra homework I have 30 minutes until it's due 6 questions my insta is bahdanz

Mathematics
1 answer:
posledela2 years ago
7 0

Answer:

lete try to help you my insta it's Cruzz_ and other letters

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Questions 16-17 | Math 1 - 0 points Solve the graph Help needed !!
iris [78.8K]

Answer:

16) The area of the circle is 25.1 units²

17) JKLM is a parallelogram but not a rectangle

Step-by-step explanation:

16) Lets talk about the area of the circle

- To find the area of the circle you must find the length of the radius

- In the problem you have the center of the circle and a point on

 the circle, so you can find the length of the radius by using the

 distance rule

* Lets solve the problem

∵ The center of the circle is (1 , 3)

∵ The point on the circle is (3 , 5)

- Using the rule of the distance between two points

* Lets revise it

- The distance between the two points (x1 , y1) and (x2 , y2) is:

 Distance = √[(x2 - x1)² + (y2 - y1)²]

∴ r = √[(3 - 1)² + (5 - 3)²] = √[4 + 4] = √8 = 2√2 units

∵ The area of the circle = πr²

∴ The area of the circle = π (2√2)² = 8π = 25.1 units²

* The area of the circle is 25.1 units²

17) To prove a quadrilateral is a parallelogram, prove that every

     to sides are parallel or equal or the two diagonal bisect

     each other

* The parallelogram can be rectangle if two adjacent sides are

  perpendicular to each other (measure of angle between them is 90°)

 or its diagonals are equal in length

- The parallel lines have equal slopes, then to prove the

  quadrilateral is a parallelogram, we will find the slopes of

  each opposite sides

* Lets find from the graph the vertices of the quadrilateral

∵ J = (0 ,2) , K (2 , 5) , L (5 , 0) , M (3 , -3)

- The opposite sides are JK , ML and JM , KL

- The slope of any line passing through point (x1 , y1) and (x2 , y2) is

 m = (y2 - y1)/(x2 - x1)

∵ The slop of JK = (5 - 2)/(2 - 0) = 3/2 ⇒ (1)

∵ The slope of LM = (-3 - 0)/(3 - 5)= -3/-2 = 3/2 ⇒ (2)

- From (1) and (2)

∴ JK // LM

∵ The slope of KL = (0 - 5)/(5 - 2) = -5/3 ⇒ (3)

∵ The slope of JM = (-3 - 2)/(3 - 0)= -5/3 ⇒ (4)

- From (3) and (4)

∴ KL // JM

∵ Each two opposite sides are parallel in the quadrilateral JKLM

∴ It is a parallelogram

- The product of the slopes of the perpendicular line is -1

* lets check the slopes of two adjacent sides in the JKLM

∵ The slope of JK = 3/2 and the slope of KL = -5/3

∵ 3/2 × -5/3 = -5/2 ≠ -1

∴ JKLM is a parallelogram but not a rectangle

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3 years ago
80<br> 3.<br> # 765 = 945<br> Arrow way
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What do you mean? I’m not sure
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3 years ago
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Great Grizzly Park sells adult tickets at price x and tickets for children 12 and under at price y. The total charge for 3 adult
alexgriva [62]

Answer:

answer is J because if we lay out the information we will understand it

5 0
3 years ago
Need an answer, please need an answer, please​
trasher [3.6K]

Answer:

Step-by-step explanation:

Area = 192 m²

Perimeter= 56 m

Width = x m

Perimeter = 56

2*(length + width) = 56

Divide the equation by 2

l + x = 56/2

l + x = 28

    l = 28 - x

Area = 192 m²

l * w = 192

(28 - x)*x = 192

28x - x*x = 192

0 = 192 - 28x + x²

x² - 28x + 192 = 0

2) Equation is a quadratic equation. The roots of this equation will the dimensions of the rectangular plot.

3) The roots represent the width and length  of the rectangle.

x² - 28x +192 = 0

Sum = -28

Product =192

Factors =  -16 , -12   {-16 +(-12) = -28  & (-12)*(-16) = 192}

x² - 28x + 192 = 0

x² - 12x - 16x + (-16)*(-12) = 0

x(x  -12) - 16(x - 12) = 0

(x - 12)(x -16) =0

x -12 = 0     ; x - 16 = 0

x = 12  ; x = 16

x = 12 ,16

4) Sum of the roots = 12 + 16 = 28

Sum of the roots = half of the perimeter

5) Product of the roots = 12*16 = 192 =  area of the rectangle.

6 0
3 years ago
Marcus is a member of a theater club. He pays a monthly fee and his movie tickets are then $5 for an unlimited number of movies
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The monthly fee is 12.55=7.5$
4 0
2 years ago
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