Ask question

Ask question

All categories

3 years ago

6

Can somebody help me out my grade are bad

2 answers:

tangare [24]3 years ago

8 0

Answer:

Mixed Number: 7 And 1/10

Improper Fraction: 71/10

Please give me Brainliest if I'm right ! :)

kodGreya [7K]3 years ago

8 0

Answer:

Mixed Number: 7 1/10

Improper Fraction: 71/10

Step-by-step explanation:

A Mixed Number is a Number with a fraction as part of it so 7 is a whole number, so this is the "number" part. .1 isnt a whole number, so you find out what the simplified form of .1 is, and you get 1/10. Put them together and you get 7 1/10. An improper fraction is where the number becomes only a fraction, no whole numbers allowed! you can find out 1 = 10/10 so this means 7 = 70/10. Add the .1 (1/10) to this and you get 71/10.

You might be interested in

CAN ANYONE HELP ME PLEASE!!!!!!

HACTEHA [7]

Not sure if this helps

3 0

3 years ago

The triangles are similar.

Radda [10]

Answer:

x=4

Process in photo...

4 0

3 years ago

What is the discriminant of 9x2 + 2 = 10x?<br> a. -356<br> b.–172<br> c.28<br> d. 72

velikii [3]

<span>Discriminant is 28 (c) First get the equation into the form: Ax^2 + Bx + C = 0 (the quadratic equation).. By subtracting 10x both sides (to get it on the other side).. 9x^2 + 2 = 10x 9x^2 - 10x + 2 = 10x - 10x 9x^2 - 10x + 2 = 0 Now the discriminant is: b^2 - 4ac The quadratic equation is Ax^2 + Bx + C = 0 Here, A = 9, B = -10 and C = 2 (-10)^2 - 4 (9)(2) = 100 - 4 (18) = 100 - 72 = 28</span>

3 0

4 years ago

Read 2 more answers

The graph of this function is shifted downwards and the axis of symmetry remains x=1. Which function below the equation of the n

Natali5045456 [20]

Answer:

$y=-x^{2}+2x$

$y=-x^{2}+2x-4$

$y=-x^{2}+2x-3$

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

The axis of symmetry is equal to the x-coordinate of the vertex

so

$x=h$

If a> 0 then the parabola open upward (vertex is a minimum)

If a< 0 then the parabola open downward (vertex is a maximum)

In this problem we have

$y=-x^{2} +2x+3$

The vertex is the point $(1,4)$ ------> observing the graph

The axis of symmetry is $x=1$

If the graph of this function is shifted downwards and the axis of symmetry remains x=1

then

The x-coordinate of the vertex of the new graph must be equal to 1

The y-coordinate of the vertex of the new graph must be less than 4

The parabola of the new graph open downward

therefore

<u>Verify each case</u>

case a) $y=-x^{2}+2x$

Convert to vertex form

$y=-(x^{2}-2x)$

$y-1=-(x^{2}-2x+1)$

$y-1=-(x-1)^{2}$

$y=-(x-1)^{2}+1$

The vertex is (1,1)

therefore

The function could be the equation of the new graph

case b) $y=-x^{2}-2x+3$

Convert to vertex form

$y-3=-(x^{2}+2x)$

$y-3-1=-(x^{2}+2x+1)$

$y-4=-(x+1)^{2}$

$y=-(x+1)^{2}+4$

The vertex is (-1,4)

therefore

The function cannot be the equation of the new graph

case c) $y=-x^{2}+2x-4$

Convert to vertex form

$y+4=-(x^{2}-2x)$

$y+4-1=-(x^{2}-2x+1)$

$y+3=-(x-1)^{2}$

$y=-(x-1)^{2}-3$

The vertex is (1,-3)

therefore

The function could be the equation of the new graph

case d) $y=-x^{2}+2x+4$

Convert to vertex form

$y-4=-(x^{2}-2x)$

$y-4-1=-(x^{2}-2x+1)$

$y-5=-(x-1)^{2}$

$y=-(x-1)^{2}+5$

The vertex is (1,5)

therefore

The function cannot be the equation of the new graph

case e) $y=-x^{2}+2x-3$

Convert to vertex form

$y+3=-(x^{2}-2x)$

$y+3-1=-(x^{2}-2x+1)$

$y+2=-(x-1)^{2}$

$y=-(x-1)^{2}-2$

The vertex is (1,-2)

therefore

The function could be the equation of the new graph

8 0

3 years ago

Cuanto es la raiz cuadrada de 123

krek1111 [17]

Answer:

11.0905365064

11.1 (rounded)

Step-by-step explanation:

$\sqrt{123} =11.090$

5 0

3 years ago