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fredd [130]
3 years ago
15

Please help with the question in the picture!!!

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

We have the measures:

1023 cm

2.3 m

8.72m

6430 mm

1200 mm

6.4 cm

2.5m

0.06km

Now let's write all those measures in the same unit, let's use meters.

We know that:

1cm = 0.01m

1mm = 0.001m

1 km = 1000m

Then, we can rewrie the measures as:

1023 cm = 1023*0.01 m = 10.23 m

2.3 m

8.72m

6430 mm = 6430*0.001 m = 6.430 m

1200mm = 1200*0.001 m = 1.2 m

6.4 cm = 6.4*0.01m =  0.064 m

2.5m

0.06km = 0.06*1000km = 60m

Then the order, from smallest to largest is:

6.4 cm

1200mm

2.3 m

2.5m

6430 mm

8.72m

1023 cm

0.06km

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Can you please help me? Thanks!!!!
ss7ja [257]
The answer is 25 degrees.

This is how you solve the equation, first you must know that the straight like ABC=180, DBC is 130, so the remaining amount is 50 degrees, BE is a bisector of ABD which means it splits ABD right down the middle. So ABE+EBD=50 degrees, 25+25=50 since both sides MUST be equal in order for BE to be a bisector of ABD.

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4 0
3 years ago
What is the approximate square root of 12 to the nearest integer
Licemer1 [7]

Answer:

3

Step-by-step explanation:

3² =  9, so  √9 = 3

4² = 16, so √16 = 4.

12 is closer to 9 than to 16, so √12 is closer to √9 than to √16.

√12 ≈ 3 (to the closest integer)

5 0
4 years ago
What are the solutions of the quadratic equation x^2=9x+6
Alexandra [31]
See Quadratic Formula and Determinant's/Delta's formula

8 0
3 years ago
The domain and range
larisa86 [58]
Domain {3, 4, 0, 4, 3}
Range {-2, 4, -2, 1, 2}

hope it helps

5 0
3 years ago
A boy of 30 kg is carrying a load of 20 kg to the top of a building of height 13m . Find his total work done . If he can do it i
r-ruslan [8.4K]

Step-by-step explanation:

g of load= 30 kg ( kilogram)

load at top of building=20 kg( kilogram)

building height=13 m(meter)

<h2>or"= total work done=?</h2>

<h3> or"=. power developed by him= ? </h3>

now ,

30*20*13÷20

again ,30*20*13

________

20

answer,= 390

5 0
3 years ago
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