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3 years ago

15

Brent and Lance leave a park on bicycles traveling at constant rates in opposite directions. After 2.5 hours, they are 85 miles

apart. If Lance bikes 2 mph faster then Brent, how fast is Lance biking?

2 answers:

stealth61 [152]3 years ago

8 0

Answer:

18 mph so B is correct 16+2= 18

Mrac [35]3 years ago

8 0

Answer:

B

Step-by-step explanation:

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Write as an equivalent expression: (3x+5)(2x+3)

VladimirAG [237]

Answer: 5x+8

Step-by-step explanation: You have to combine like terms.

3x+2x=5x

5+3=8

= 5x+8

4 0

3 years ago

i beg of yall a crown, 5 stars, a heart and a ty comment to answer my questions iv posted on my profile, ill be posting more too

Over [174]

Answer:

I would say the answer is $5.00/lb

Have a wonderful day!

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3 years ago

The Blue devils had won 37.5 games. they had played 24 games altogether. how may games had they won?

lubasha [3.4K]

The Blue Devils are trying to sell us a bridge and a bill of goods.
But we are sharp, and we are not falling for their story.

We are smart enough to spot two glaring weaknesses in their story.

1). There is no way to win .5 of a game.

2). There is no way to win 37 games if you've
only played 24 so far.

4 0

3 years ago

Miss Berk has 8 pairs of pajama pants and 3 pairs of slippers. Three pairs of the pajama pants are Harry Potter themed and one p

shusha [124]

The probability that both items will be Harry Potter themed is 1/8.

<u>Step-by-step explanation:</u>

Total Number of pajama pants n(P) =8

Total number of slippers n(S)= 3

Number of Harry Potter themed Pajama pants n(H.P)=3

Number of Harry Potter themed slippers n(H.S)=1

We have to determine the probability of selecting pants and slippers that are both Harry Potter themed.

If two events A and B are independent, then the probability of A and B is given by

P(A and B)=P(A)*P(B)

Here the events selecting Harry potter themed pants and selecting harry Potter themed slippers are independent.

$P(Harry\ Potter\ pants)=\frac{n(H.P)}{n(P)}$

$=\frac{3}{8}$

$P(Harry\ Potter\ slippers)=\frac{n(H.S)}{n(S)} \\ =1/3$

$P(Harry\ Potter\ pants\ and\ Harry\ Potter\ slippers)=P(Harry Potter pants)\times P(Harry potter slippers)$

$=\frac{3}{8}\times \frac{1}{3} =\frac{1}{8}$

Hence probability of selecting Harry potter themed pants and Harry potter themed slippers is 1/8

3 0

3 years ago

Read 2 more answers

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

So

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

So

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

3 years ago