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maw [93]
3 years ago
15

Brent and Lance leave a park on bicycles traveling at constant rates in opposite directions. After 2.5 hours, they are 85 miles

apart. If Lance bikes 2 mph faster then Brent, how fast is Lance biking?
Mathematics
2 answers:
stealth61 [152]3 years ago
8 0

Answer:

18 mph so B is correct 16+2= 18

Mrac [35]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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After simplification, the value of 1-2/1(1+2)-3/(1+2)(1+2+3)-4/(1+2+3)(1+2+3+4)-...-100/(1+2+...+99)(1+2+...+100)
vladimir1956 [14]

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3 years ago
Clare, David and Elizabeth share 90 marbles in the ratio 4: 5: 6. Calculate the number of marbles that Clare receives
Rzqust [24]
Claire receives 24 marbles. David gets 30 marbles and Elizabeth gets 36 marbles.


4x+5x+6x=90

15x=90

x=6

4(6)=24 for Claire

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6(6)= 36 for Elizabeth
6 0
3 years ago
Tam multiplied 2.13 and 4.62, as shown. But he forgot to put a decimal point in his
yuradex [85]
The decimal gives after the 9. There are four places behind the decimal between the two numbers being multiplied so there have to be 4 places behind the decimal in your answer.
8 0
3 years ago
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A particle travels along a straight line with a velocity of v(t)=3e^(-1/2)sin(2t) meters per second. What is the total distance
KatRina [158]
Solve for v(t)=0 over the interval [0,2] 

<span>sin(pi)<0, try t=pi/2, </span>

<span>3e^(-pi/4)sin(pi)= 0, so the interval 0 to pi/2 the particle travels forward [0,pi/2), then it goes negative for the rest of the interval (pi/2,2) and travels backward. </span>

<span>total distance = |integral 0 to pi/2 v(t) dt| + |integral pi/2 to 2 v(t) dt|
</span>∫[0 to π/2] v(t) dt = ∫[0 to π/2] (3 e^(−t/2) sin(2t)) dt 
<span>. . . . . . . . . . . . . = ∫[0 to π/2] (3 e^(−t/2) sin(2t)) dt </span>
<span>. . . . . . . . . . . . . = −6/17 e^(−t/2) (sin(2t) + 4cos(2t)) |[0 to π/2] </span>
<span>. . . . . . . . . . . . . = −6/17 (e^(−π/4) (sin(π) + 4cos(π)) − e^(0) (sin(0) + 4cos(0))) </span>
<span>. . . . . . . . . . . . . = −6/17 (e^(−π/4) (0 − 4) − (0 + 4)) </span>
<span>. . . . . . . . . . . . . = −6/17 (−4e^(−π/4) − 4) </span>
<span>. . . . . . . . . . . . . = 24/17 (e^(−π/4) + 1) </span>
<span>. . . . . . . . . . . . . = 2.05544 
</span>
∫[π/2 to 2] v(t) dt = ∫[π/2 to 2] (3 e^(−t/2) sin(2t)) dt 
<span>. . . . . . . . . . . . . = ∫[π/2 to 2] (3 e^(−t/2) sin(2t)) dt </span>
<span>. . . . . . . . . . . . . = −6/17 e^(−t/2) (sin(2t) + 4cos(2t)) |[π/2 to 2] </span>
<span>. . . . . . . . . . . . . = −6/17 (e^(−1) (sin(4) + 4cos(4)) − e^(−π/4) (sin(π) + 4cos(π))) </span>
<span>. . . . . . . . . . . . . = −6/17 ( (sin(4)+4cos(4))/e − e^(−π/4) (0 − 4)) </span>
<span>. . . . . . . . . . . . . = −6/17 ( (sin(4)+4cos(4))/e + 4e^(−π/4)) </span>
<span>. . . . . . . . . . . . . = −0.205938 </span><span> </span>

<span>when you add absolute values of area you get actual distance traveled: </span>
<span>∫[0 to π/2] v(t) dt − ∫[π/2 to 2] v(t) dt </span>
<span>= 2.05544 − (−0.205938) </span>
<span>= 2.05544 + 0.205938 </span>
<span>= 2.261378 </span>
3 0
3 years ago
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Snezhnost [94]

Answer:

250?

Step-by-step explanation:

I Don't Know If It's 250 because 250 Is Half Of 200, And Half Less Of 300, So I Guess It's 250? I Think I'm Wrong!

3 0
4 years ago
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